Work Area Length Exceeded

[Former Member]

I'm getting an error message that says 'The work area ITABTWO is not long enough.'

How do I extend the length of my work area.

//zdolsarc03 is a structure with caseid, SearchFld, and a Value (component type RSDSSELOPT <which is the structure of generic select-option for dynamic selections>)

ZDOLTARC03 is a table similar to the structure ZDOLSARC03, however its value is of data element: rsdsselop_ not rsdsselopT.

Could this be the reason why the WA's size is exceeded?

DATA: ITABTWO LIKE ZDOLSARC03 OCCURS 0,
      WATWO LIKE ZDOLSARC03.
SELECT * INTO TABLE ITABTWO FROM ZDOLTARC03
        WHERE SEARCHFLD EQ WAONE-SEARCHFLD ORDER BY SEARCHFLD.

N L

[Former Member]

I'm getting an error message that says 'The work area ITABTWO is not long enough.'

How do I extend the length of my work area.

//zdolsarc03 is a structure with caseid, SearchFld, and a Value (component type RSDSSELOPT <which is the structure of generic select-option for dynamic selections>)

ZDOLTARC03 is a table similar to the structure ZDOLSARC03, however its value is of data element: rsdsselop_ not rsdsselopT.

Could this be the reason why the WA's size is exceeded?

DATA: ITABTWO LIKE ZDOLSARC03 OCCURS 0,
      WATWO LIKE ZDOLSARC03.
SELECT * INTO TABLE ITABTWO FROM ZDOLTARC03
        WHERE SEARCHFLD EQ WAONE-SEARCHFLD ORDER BY SEARCHFLD.

N L

[Former Member]

this is how it should be :

ZDOLSARC03 - structure of DDIC type

ZDOLTARC03 - table of DDIC type

It should <b>not be similar</b>, but have exactly the <b>same number of elements and in the same order</b>.

If ZDOLTARC03 and ZDOLSARC03 have different number of elements, your program will give an error.

Regards,

Subramanian V.

[RichHeilman]

Try this....

SELECT *
   INTO <b>CORRESPONDING FIELDS OF</b>
                TABLE itaBTWO       
                    FROM ZDOLTARC03 
       WHERE SEARCHFLD EQ WAONE-SEARCHFLD
                      ORDER BY SEARCHFLD.

Regards,

Rich Heilman