Validate String with a pattern

[Former Member]

How can we validate the string with a pattern?

eg. Value should always be of the format C-DDD,

where C is a character (A-Z or a-z) and

D represents a digit(0-9)

Valid forms are A-001, A-987, Z-098 and

not valid forms are A-01, 1-A01, 1- 0A0, A-A01, A-0001

Say internal table contains values like this.

F1 F2 F3

1 00001 A-001

2 00001 A-A01

3 00001 B-909

4 00001 Z-01

5 00001 k-0001

Valid records are 1 and 3.

[Former Member]

LOOP AT itab.

  IF itab-f3+0(1) CA sy-abcde.
    IF itab-f3+1(1) EQ '-'.
      IF itab-f3+2(3) CO '0123456789'.
*     Valid
      ELSE.
* Invalid
      ENDIF.
    ELSE.
* Invalid
    ENDIF.
  ELSE.
* Invalid.
  ENDIF.
ENDLOOP.

[Former Member]

Is there any other possible way of coding it, this actually leads to performance issue.

or say for example if the pattern is C-LOCATION or C-location?

where c can be (A-Z or a-z)...

[Former Member]

use this logic

data: char,
         num type n,
         str(4),
        strn(6).

char = 'A'. " u can take from user as well
num = 1000.
str = num.

concatenate char str into strn." u can also use saperate key word as well

Regards

Prakash Varun

[Former Member]

Hi,

you can use regular expressions for this, e.g.:

  FIND ALL OCCURRENCES OF REGEX '[a-z,A-Z]-[0-9]{3}[ [:blank:] ]'
       IN TABLE t_data
       RESPECTING CASE
       RESULTS t_results.

Note that in the above example all fields in the table will be checked. If this is not practical for your use you can use a LOOP and FIND on the table field.

Note that line 5 in your example also matches the pattern you have given. If you really do not want to see this as valid you will have to use the pattern: '[A-Z]-[0-9][ [:blank:] ]'. The addition of [ [:blank:] ] is only needed if your field is longer than the pattern, i.e. 5 characters.

Good luck,

Gert.

Edit: This will also be pretty efficient.

Edited by: Gert Beukema on Jul 15, 2008 10:36 AM