uregent

[former_member206396]

A B

-

---

10 100

20 100

20 100

20 100

30 100

30 100

30 100

here i need to count for a = 10 how many records are there?

i.e., here for 10, 1 record

20, 3 records

30, 3 records

i want to display this things in alv output , so i need to reserve these values..

could you pls help me out..

[former_member206396]

A B

-

---

10 100

20 100

20 100

20 100

30 100

30 100

30 100

here i need to count for a = 10 how many records are there?

i.e., here for 10, 1 record

20, 3 records

30, 3 records

i want to display this things in alv output , so i need to reserve these values..

could you pls help me out..

[Former Member]

Do this

Copy the internal table into ITAB2.

SORT ITAB2 BY A.

DELETE ADJACENT DUPLICATES FROM ITAB2 COMPARING A.

LOOP AT ITAB2.

LOOP AT ITAB1 WHERE A = ITAB2-A.

COUNT = COUNT + 1.

ENDLOOP.

Here update the count of the column wherever you want.

CLEAR COUNT.

ENDLOOP.

Regards,

Ravi

Note : Please mark all the helpful answers

[Former Member]

Hi Ramakrishna,

Try with this code.

DATA:

BEGIN OF I_CNT_TAB OCCURS 0,

A TYPE A,

COUNT TYPE I,

END OF I_CNT_TAB.

DATA WA_CNT_TAB LIKE LINE OF I_CNT_TAB.

SORT ITAB BY A.

LOOP AT ITAB.

AT NEW A.

CLEAR V_COUNT.

ENDAT.

V_COUNT = V_COUNT + 1.

AT END OF A.

WA_CNT_TAB-A = ITAB-A.

WA_CNT_TAB-COUNT = V_COUNT.

APPEND WA_CNT_TAB TO I_CNT_TAB.

CLEAR WA_CNT_TAB.

ENDAT.

ENDLOOP.

Thanks,

Vinay

[Former Member]

hi,

data C type i.

Sort Itab by A.

Loop at itab.

c = c + 1.

at end of A.

Write C .

clear C.

end at.

endloop.

[Former Member]

Hi Ram,

SORT lit_output BY A.

LOOP AT lit_output INTO wa_output.

wa_op-A = wa_output-A.

wa_op-cnt = wa_op-cnt + 1.

AT END OF A.

APPEND wa_op TO lit_op.

clear wa_op-cnt.

ENDAT.

ENDLOOP.

Rgds,

Prakash

<b>Please Reward points if helpful</b>

[santhosh_patil]

hi,

chech the below code this may help you.

using this you can have count in another table for each item A....

data : begin of itab occurs 0,

a type i,

b type i,

end of itab.

data : begin of itab1 occurs 0,

a type i,

count type i,

end of itab1.

data : count type i.

itab-a = 10.

itab-b = 100.

append itab.

itab-a = 10.

itab-b = 100.

append itab.

itab-a = 20.

itab-b = 100.

append itab.

itab-a = 20.

itab-b = 100.

append itab.

itab-a = 20.

itab-b = 100.

append itab.

itab-a = 20.

itab-b = 100.

append itab.

itab-a = 30.

itab-b = 100.

append itab.

itab-a = 40.

itab-b = 100.

append itab.

itab-a = 40.

itab-b = 100.

append itab.

itab-a = 50.

itab-b = 100.

append itab.

clear count.

loop at itab.

count = count + 1.

at end of a.

itab1-a = itab-a.

itab1-count = count.

append itab1.

clear : count,

itab.

endat.

endloop.

uline.

write / ' contents of itab'.

uline.

loop at itab.

write : / itab-a , itab-b.

endloop.

uline.

write / ' contents of itab1'.

uline.

loop at itab1.

write : / itab1-a , itab1-count.

endloop.

output:

contents of itab

10 100

10 100

20 100

20 100

20 100

20 100

30 100

40 100

40 100

50 100

contents of itab1

10 2

20 4

30 1

40 2

50 1

[Former Member]

Hi,

Consider this code. Just copy and execute.

I have made use of <b>AT END OF...ENDAT</b> for counting.

REPORT abc.

TYPES : BEGIN OF str_test,
        a(5),
        b(5),
        END OF str_test.

DATA : it_test TYPE STANDARD TABLE OF str_test WITH HEADER LINE,
       cnt TYPE i.

it_test-a = 10.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.

it_test-a = 10.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.

it_test-a = 10.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.

it_test-a = 20.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.

it_test-a = 20.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.


it_test-a = 30.
it_test-b = 100.
APPEND it_test.
CLEAR it_test.


SORT it_test BY a.


LOOP AT it_test.

  cnt = cnt + 1.
  AT END OF a.
    WRITE : / 'Field  A with value :',
               it_test-a,
               'No of entries:',
               cnt.

    CLEAR cnt.   <b>"Dont forget to clear</b>

  ENDAT.


ENDLOOP.



The ouput will be in this manner.

Field  A with value :   10  No of entries:          3
Field  A with value :   20  No of entries:          2
Field  A with value :   30  No of entries:          1

Regards,

Arun Sambargi.

Message was edited by: Arun Sambargi