Type P issue

[Former Member]

Hello gurus,

I am dividing 0.7600 by 1000 --- the value shoud be 0.00076

The variable in which this value is calculated is type P decimal 6.

Now after dividing i get a value equals 0.000008.

I dont know how to go abt it.

also when i changed the type of the variable to F then i got an exponential value in the output.

Please help me.

Regards,

Roshan Lilaram Wadhwani.

[Former Member]

Hi,

Welcome to SDN.

declare type P decimal 9 in place of type P decimal 6.

Regards,

Anirban

[Former Member]

Sorry sir,

On trying that i was getting a value 0.000000008.

If you dont mind then can i ask you on what basis did you ask me to change it to 9, does this type P works on multiples of 3???

Regards,

Roshan.

[RichHeilman]

I'm not seeing the same behavoir, this code outputs 0.000760

data: p type p DECIMALS 6 value '0.7600'.

p = p / 1000.

write:/ p .

Regards,

Rich Heilman

[Former Member]

Hello,

Thanks for replying to my query.

kalc-value = 0.7600

ekpo-peinh = 1000

gv_unitprice = KALC-VALUE / EKPO-PEINH .

This is my basic requirement.

here i am unable to get that 0.000760

[JozsefSzikszai]

kalc-value has 4 decimal places in Data Dictionary. How did you define it in your program?

[Former Member]

Hello,

Actually this program is a copy of the standard program.

We are directly using it, we have not defined it explicitly.

Regards,

Roshan.

[JozsefSzikszai]

Program Attributes ==> Fixed point arithmetic is checked?

[Former Member]

Hello,

Thanks for the reply.

Fixed point arithmetic is not checked

Regards,

Roshan.

[JozsefSzikszai]

tha pls. check and try agaon. also check the definition of calc-value!

[Former Member]

Hello,

Sir, This is an include program, we dont have that option there and in the main program it is not checked.

KALC-VALUE is a standard field with decimal places 4.

Regards,

Roshan.

[JozsefSzikszai]

>

> KALC-VALUE is a standard field with decimal places 4.

in this case, there is no chance, the value of 0.00076 will be automatically rounded to 0....8 by the system (because of the 4 decimals).

you say the copied program still using the standard include? probably you can copy the include as well and make the necessary modifications

[Former Member]

Hello,

Sorry to offend you but what exactly do you mean by " there is no chance, the value of 0.00076 will be automatically rounded to 0....8 by the system (because of the 4 decimals)."

should i transfer the below two variables to decimal 6 local variables and then they shoud be divided.

kalc-value = 0.7600

ekpo-peinh = 1000

gv_unitprice = KALC-VALUE / EKPO-PEINH .

Regards,

Roshan Lilaram.

[naimesh_patel]

It looks like, your main program does not have the "Fixed Point Airtmetic" checkbox set in the Program > Attributes.

data: gv_unitprice type p decimals 8,
      l_value      type p decimals 4,
      l_peinh      type ekpo-peinh.

l_value = '0.7600'.
l_peinh = 1000.

gv_unitprice = l_VALUE / l_PEINH .
write: gv_unitprice.

With the "Fixed Point Airthmetic" checkbox set, I got the this result:

      0.00076000 

Without the "Fixed Point Airthmetic" checkbox set, I got the this result:

      0.00000008

Regards,

Naimesh Patel

[Former Member]

Hello Roshan.

In Agreement with Rich.

His code works fine and may be you might have divided with something else which has given you "0.000008"

Good Luck & Regards.

Harsh Dave