type conversion

[Former Member]

hi folks,

Need some urgent help in this regard.

I have this character data(size 44) to convert that into integer value. I used the move statement and moved the value to a string and then to the integer. it is giving SHORT DUMP SAYING IT IS AN OVERFLOW CONDITION. The data in the variable is huge and I need to convert it into integer as it is.

Also I am wondering that after converting into integer I need to mutiply the numbers in the positions 1,3.. with 2,and even positioned numbers with 1. How can i track them separately if I am using the integer type?

Because I need to perform arithematic calculations I wanted to convert into integer.

If there is a better way do suggest me?

thanks

Thanks for your help in advance. it would really help.

Santhosh

[Former Member]

Hi Santhosh,

Here is a small piece of code to achieve what you wanted to achieve.

DATA: v_char44(44) TYPE c,
      v_value      TYPE i,
      v_digit      TYPE i,
      v_oddoreven  TYPE i,
      v_pos        TYPE i.


START-OF-SELECTION.
  v_char44 = '12345678901234567890123456789012345678901234'.
*-- get rid of leading spaces.
  SHIFT v_char44 LEFT DELETING LEADING space.

  DO 44 TIMES.
    v_pos = sy-index - 1.
    IF v_char44+0(1) IS INITIAL.
*-- no more filled in positions, exit
      EXIT.
    ENDIF.
    v_digit = v_char44+v_pos(1).
    v_oddoreven = sy-index MOD 2.
    IF v_oddoreven = 0.
*-- even number
      v_value = v_value + v_digit.
    ELSE.
*-- odd number
      v_value = v_value + ( v_digit * 2 ).
    ENDIF.
  ENDDO.

  WRITE: v_value.

Hope it helps,

Srinivas

[Former Member]

hey srinivas thanks a lot. it really helped. Here is the situation. It is a bit complicated code if you could help here that would solve my problem.

For example take the number(the real number is 43 characters) like this:

4 1 2 9 7 9 6

2 1 2 1 2 1 2 ( mutiply the odd digit numbers with 2 and

even with 1)

8 1 4 9 14 9 12

Now where the result is double digit, I have add the double digit numbers

I am confused at how to track the double digits out here and add them all.......

8 1 4 9 5 9 3

Now add these numbers = 39/10 = 3 remainder 9

last step 10 -9 = 1 This is the number I want it to be converted back into character format.

I am working on it.. Your input would help me out here.

Thanks a lot.

Santhosh

[Former Member]

Numerology in SAP?

Is this perhaps for sales forecasting...

Brad

[Former Member]

it is for the scanline code and I need to generate this number after all these operations it is a 43 character variable using which I need to perform these steps and generate the number.

Santhosh

[Former Member]

Here is the modified code.

DATA: v_char44(44) TYPE c,
      v_value(2)   TYPE n,
      v_digit      TYPE n,
      v_oddoreven  TYPE i,
      v_pos        TYPE i,
      v_result     TYPE i,
      v_value_i    TYPE i.


START-OF-SELECTION.
  v_char44 = '4129796'.
*-- get rid of leading spaces.
  SHIFT v_char44 LEFT DELETING LEADING space.

  DO 44 TIMES.
    v_pos = sy-index - 1.
    IF v_char44+0(1) IS INITIAL.
*-- no more filled in positions, exit
      EXIT.
    ENDIF.
    v_digit = v_char44+v_pos(1).
    v_oddoreven = sy-index MOD 2.
    v_value = v_digit.
    IF v_oddoreven = 0.
*-- even number,
      v_value_i = v_value.
    ELSE.
*-- odd number
      v_value = v_digit * 2.
      IF v_value > 9.
*-- number has two digits
        v_value_i = v_value+0(1) + v_value+1(1).
      ELSE.
        v_value_i = v_value.
      ENDIF.
    ENDIF.
    v_result = v_value_i + v_result.
  ENDDO.

  CLEAR: v_value_i, v_digit, v_value.

  v_value_i = v_result MOD 10.

  CLEAR v_result.
  v_result =  10 - v_value_i.
  WRITE:/ v_result.

Srinivas

[Former Member]

Thank you Srinivas. It solved my problem. I really appreciate your help in this regard. have nice weekend.