substring

[Former Member]

dear Gurus

I have string "AA000PGS01901", i want to store last 5 characters of the string into a variable. Pls.help me in this.

regards

Prasad

[Former Member]

Hi,

code like below.

DATA:str type string value 'AA000PGS01901'.
data:sub_str(5),len(2) type n.
len = strlen( str ).
if len GE 5.
  len = len - 5.
else.
  len = 0.
endif.

sub_str = str+len.
write:/ sub_str.

rgds,

bharat.

[Former Member]

pass this to a variable say A

then B = A+8(5).

[Former Member]

Hi,

data: v_string(50), v_result(50),

v_len type i.

v_string = 'AA000PGS01901'.

v_len = strlen( v_string ).

if v_len ge 5.

v_len = v_len - 5.

v_result = v_string+v_len(5).

write:/ v_result.

endif.

Edited by: Velangini Showry Maria Kumar Bandanadham on Apr 15, 2008 8:54 AM

[Former Member]

Hi Prasad,

You can get the string length by STRLEN(STRING).then subract 5 from the count and just take the last 5 characters.I wil give you the example.

i = strlen(str)

i1 = i - 5.

Var=str+i1(5).

try this.it should be helpful

Thanks,

Bala

[Former Member]

Check this code.

DATA: l_string(10) TYPE c VALUE 'ABC01005',
      l_len TYPE i,
      l_count TYPE i VALUE -1.

 l_len = STRLEN( l_string ).
 l_count = l_len - 5.
 l_value = l_string+l_count(5).
 write: l_value.

[Former Member]

Hi,

data: var1 type string.

parameters: s1(100) type c.

data: v1 type i.

data: v2 type i value 5.

data: v3 type i value 5.

v1 = strlen( s1 ).

v2 = v1 - v2.

var1 = s1+v2(v3).

write: var1.

[Former Member]

Hi,

data: string1(10) type c.

data: string2(5) type c.

data strlength type n.

string1 = 'sampl10203'.

strlength = strlen( string1 ).

strlength = strlength - 5.

string2 = string1+strlength(5).

write: / string2.

I think it is useful for you.