string

[Former Member]

Hi Experts,

i have a string like this.

str = '00000003379#212RegVNegNoticeHLA.aspx.xml' So i want to read n.of characters from # to begin of the string. ie 00000003379#.The value for str will come dinamically.How can we do this?

Regards

[Former Member]

Hi Ravi,

Try the "Split" statement :

split str at '#' into w_rec01 w_rec02.

Best Regards,

Erwan

[Former Member]

1. Split the string at symbol # and store it in a variable

2. find the length of the string variable

regards

vivek

• award points if this helps

[Former Member]

Hi Experts

I have one long string and from which i should take only last 4 chars

how to do it

please tell me

rajesh

[Former Member]

Hello Ravi,

Use this code.

DATA: STR1 TYPE STRING,

STR2 TYPE STRING.

SPLIT STR AT '#' INTO STR1 STR2.

CONCATENATE STR1 '#' INTO STR1.

write: STR1.

If useful reward.

Vasanth

[Former Member]

Hi,

Thanks for replies.

Problem is i am gettin value for str in debugging like this.

str = 00000003758#Account_Agreements-Combination.aspx.xml #

So at the end some where i am getting one more #.

[Former Member]

str = 00000003758#Account_Agreements-Combination.aspx.xml #

v_len = strlen( str ).

v_len = v_len - 1.

str = str+0(v_len).

now use split at #

split str at '#' into v_num v_new.

Regards,

Ravi

[Former Member]

ok , if you are uploading it from an excel file you will get that # at last , so add 3 more line to remove that

len = strlen( str ).
len = len - 1.
str = str+0(len).

so this will remove the last # from str

[suresh_datti]

what if the second '#' is somewhere in between & not always at the end?

you can use the following to cover that scenario..

report  zp_string.
data w_str type 
     string value '00000003758#Account_Agre#ements-#Combination.aspx.xml #'.
data w_len type i.
data: w_str2 type string.

search w_str for '#' and mark.
w_len = sy-fdpos.
w_str2 = w_str+0(w_len).
write:/ w_str.
write:/ w_str2.

~Suresh

[Former Member]

Hi Ravi,

You may n no of #'s in your line. To get length of string upto last '#' then try with this code.

DATA: L_LOC TYPE I,

L_LNG TYPE I,

L_CMD TYPE STRING,

L_FIL TYPE STRING,

STR TYPE STRING.

L_LENGTH = STRLEN( STR ).

L_LOC = 1.

WHILE SY-SUBRC = 0.

SEARCH STR FOR '#' STARTING AT L_LOC.

IF SY-FDPOS > 0.

ADD SY-FDPOS TO L_LOC.

L_CMD = STR(L_LOC).

L_LNG = L_LENGTH - L_LOC.

L_FIL = STR+L_LOC(L_LNG).

ELSE.

ADD 1 TO L_LOC.

ENDIF.

ENDWHILE.

WRITE:/ 'Length of string upto last # is ', L_LOC.

Thanks,

Vinay

[Former Member]

Hi All,

thanks.

[anversha_s]

hi,

try this.

SEARCH string for '#'.

l_from = sy-fdpos - 1.

search string for '#' starting at l_from.

l_to = sy-fdpos - 1.

l_len = l_to - l_from.

v_cutout = string+l_from(l_len).

Regards,

anver

[Former Member]

lstr --> is your string

split lstr at '#' into lval lfile.

llen = strlen( lval ) + 1. (1 is to include the count for #).

Regards

Anurag

[Former Member]

Hi Ravi,

 chk this

REPORT YCHATEST.

DATA : STR TYPE STRING,
       STR1 TYPE STRING,
       STR2 TYPE STRING,
       LEN TYPE I.

STR = '00000003379#212RegVNegNoticeHLA.aspx.xml'.

SPLIT STR AT '#' INTO STR1 STR2.

LEN = STRLEN( STR1 ).
LEN = LEN + 1.      " to include #

WRITE : LEN.

[Former Member]

Hi Ravi,

Try this:

split str at '#' into str1 str2.

if sy-subrc = 0.

l_count = strlen( str1 ).

endif.

Dharitree

[Former Member]

Hi,

use below logic

data lv_len type i.

str = '00000003379#212RegVNegNoticeHLA.aspx.xml'

search str for '#'.

lv_len = sy-fdpos - 1.

lv_len will have length of string.

<b>or

split str at '#' str1 str2.

lv_len = strlen(str1).</b>

Regards

amole