string contains special chars

[Former Member]

Hi there,

If given string contains a special character in the first position..i need to delete the character from the string.

please suggest a way..

[Former Member]

Hi there,

If given string contains a special character in the first position..i need to delete the character from the string.

please suggest a way..

[Former Member]

Hi Tuborg,

Use offset to delete it.

Refer this seudo code :

data : d_string type string value '@abcdef'.

d_string = d_string+1(6).

Regards,

Hemant

[former_member188827]

if str+0(1) eq 'your_special_character>'.

str+0(1) eq ' '.

shift str left deleting leading space.

endif.

[Former Member]

creaate a range containing all the alphabets.. both small n capital...

data: str1(10).

if str1+0(1) NOT IN range.

SHIFT str1 BY 1 PLACES LEFT.

endif.

[Former Member]

hi

good

use strlen and get the length of the string than delete the first letter as per the position starting from 0,

thanks

mrutyun^

[Former Member]

It's clunky, but try this:

• To replace special character with space.

data: w_val type string.

move old_string+0(1) to w_val.

replace first occurance of w_val in old_string with space.

OR

• To remove it entirely

shift old_string by 1 places left. " Shifts string to left and drops off characters to left.

Steve

[Former Member]

thanks.

but not always the first char will be the special char..How to check the first char is the special char?

[Former Member]

any ideas??

[Former Member]

by creating a range of the aplhabets .. you are defining all the non-special characters...

as you cant possibly list down all the characters...

so in the condition check if string+0(1) i.e. 1st char of string is ther in the range or not..

if not in the range... that is your special character... remove it

[former_member188827]

if str+0(1) eq 'your_special_character>'.

str+0(1) eq ' '.

shift str left deleting leading space.

endif.

str+0(1) checks only da first character. if it is special character it 'll delete it else da string 'll remain same.

try da code n den leme kno if its working or not

[Former Member]

Hi,

If you knw the Ascii codes, then its pretty simple:

if string+0(1) GE 65 and string+0(1) LE 91.
...
endif.

Best regards,

Prashant