‎2007 Sep 10 8:42 AM
Hi. Could You give me some tip how to solve such problem:
REPORT ZWOP_TEST5 .
DATA: BEGIN OF a OCCURS 0,
value1 TYPE c,
END OF a.
DATA: BEGIN OF b OCCURS 0,
value2 TYPE c,
END OF b.
TYPES: BEGIN OF _itab.
INCLUDE STRUCTURE a.
INCLUDE STRUCTURE b .
TYPES: END OF _itab.
DATA: itab TYPE STANDARD TABLE OF _itab WITH HEADER LINE.
a-value1 = 'A'. APPEND a.
a-value1 = 'B'. APPEND a.
a-value1 = 'C'. APPEND a.
a-value1 = 'D'. APPEND a.
SORT a BY value1.
b-value2 = 'A'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'C'. APPEND b.
SORT b BY value2So it's
a | b
--|--
A | A
B | B
C | B
D | CI want itab looks sth like that:
v1|v2
--|--
A | A
B | B
| B
C | C
D |Sorry, I hadn't precised my post.
I neet to <b>fill</b> table itab with values from a & b creating 'pairs'.
Message was edited by:
Piotr Wojciechowski
‎2007 Sep 10 9:14 AM
DATA: BEGIN OF a OCCURS 0,
value1 TYPE c,
END OF a.
DATA: BEGIN OF b OCCURS 0,
value2 TYPE c,
END OF b.
DATA: f TYPE i,
f1 TYPE i.
TYPES: BEGIN OF _itab.
INCLUDE STRUCTURE a.
INCLUDE STRUCTURE b .
TYPES: END OF _itab.
DATA: itab TYPE STANDARD TABLE OF _itab WITH HEADER LINE.
a-value1 = 'A'. APPEND a.
a-value1 = 'B'. APPEND a.
a-value1 = 'C'. APPEND a.
a-value1 = 'D'. APPEND a.
SORT a BY value1.
b-value2 = 'A'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'C'. APPEND b.
SORT b BY value2.
LOOP AT a.
f = 0.
f1 = 0.
LOOP AT b.
CLEAR itab.
IF ( a-value1 = b-value2 ).
f1 = 1.
IF f = 0.
f = 1.
itab-value1 = a-value1.
itab-value2 = b-value2.
ELSE.
itab-value2 = b-value2.
ENDIF.
APPEND itab.
ENDIF.
ENDLOOP.
CLEAR itab.
IF f1 = 0.
itab-value1 = a-value1.
APPEND itab.
ENDIF.
ENDLOOP.
LOOP AT itab.
WRITE:/ itab-value1,itab-value2.
ENDLOOP.
‎2007 Sep 10 8:49 AM
hi,
try like this,
a-value1 = 'A'. APPEND a.
a-value1 = 'B'. APPEND a.
a-value1 = ' '. APPEND a. // OR USE KEYWORD NULL
a-value1 = 'C'. APPEND a.
a-value1 = 'D'. APPEND a.
b-value2 = 'A'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'C'. APPEND b.
b-value2 = ' '. APPEND b.
IF HELPFUL REWARD SOME POINTS.
WITH REGARDS,
SURESH ALURI.
‎2007 Sep 10 8:49 AM
‎2007 Sep 10 8:52 AM
Sorry, I hadn't precised my post.
I neet to <b>fill</b> table itab with values from a & b creating 'pairs'.
‎2007 Sep 10 8:50 AM
Hi,
do like this.
DATA: BEGIN OF a OCCURS 0,
value1 TYPE c,
END OF a.
DATA: BEGIN OF b OCCURS 0,
value2 TYPE c,
END OF b.
TYPES: BEGIN OF _itab.
INCLUDE STRUCTURE a.
INCLUDE STRUCTURE b .
TYPES: END OF _itab.
DATA: itab TYPE STANDARD TABLE OF _itab WITH HEADER LINE.
itab-value1 = 'A'.
itab-value2 = 'A'. APPEND itab.
itab-value1 = 'B'.
itab-value2 = 'B'. APPEND itab.
itab-value1 = 'C'.
itab-value2 = 'B'. APPEND itab.
itab-value1 = 'D'.
itab-value2 = 'C'. APPEND itab.
sort itab by value1 value2 ASCENDING.
LOOP AT itab.
write:/ itab-value1,itab-value2.
ENDLOOP.
<b>reward if helpful</b>
rgds,
bharat.
‎2007 Sep 10 9:14 AM
DATA: BEGIN OF a OCCURS 0,
value1 TYPE c,
END OF a.
DATA: BEGIN OF b OCCURS 0,
value2 TYPE c,
END OF b.
DATA: f TYPE i,
f1 TYPE i.
TYPES: BEGIN OF _itab.
INCLUDE STRUCTURE a.
INCLUDE STRUCTURE b .
TYPES: END OF _itab.
DATA: itab TYPE STANDARD TABLE OF _itab WITH HEADER LINE.
a-value1 = 'A'. APPEND a.
a-value1 = 'B'. APPEND a.
a-value1 = 'C'. APPEND a.
a-value1 = 'D'. APPEND a.
SORT a BY value1.
b-value2 = 'A'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'B'. APPEND b.
b-value2 = 'C'. APPEND b.
SORT b BY value2.
LOOP AT a.
f = 0.
f1 = 0.
LOOP AT b.
CLEAR itab.
IF ( a-value1 = b-value2 ).
f1 = 1.
IF f = 0.
f = 1.
itab-value1 = a-value1.
itab-value2 = b-value2.
ELSE.
itab-value2 = b-value2.
ENDIF.
APPEND itab.
ENDIF.
ENDLOOP.
CLEAR itab.
IF f1 = 0.
itab-value1 = a-value1.
APPEND itab.
ENDIF.
ENDLOOP.
LOOP AT itab.
WRITE:/ itab-value1,itab-value2.
ENDLOOP.