simple logic

[Former Member]

hi,

its an error if the variable x does not lie in a set of numbers like,

ie, x must be in between 8000 to 8500 or 9000 and 9500

or 10000 and 10500 etc this way there are a 6 set of ranges.

so can any one help how to do this,

i thought of doing like this:

if not ( 8000 < x < 8500 ).

if not ( 8000 < x < 8500 ).

if not ( 9000 < x < 9500 ).

if not ( 10000 < x < 10500 ).

if not ( 11000 < x < 11500 ).

if not ( 12000 < x < 12500 ).

e_flag = 1.

endif.

endif.

endif.

endif.

endif.

endif.

but i doubt will it work, dont know, can some one suggest a proffessional way.

thank you.

[Former Member]

hi,

ranges : r_value for i.

r_value-low = 8000.

r_value-high = 8500.

append r_value.

repeat this for all set of values.

if not x in r_value.

your logic.

endif.

thanks

Mahesh

Message was edited by:

I Can Solve It

[Former Member]

data : begin of x_range,

SIGN TYPE DDSIGN ,

OPTION TYPE DDOPTION,

low type i,

high type i,

end of x_range.

ranges : r_value for i.

x_value-low = 8000.

x_value-high = 8500.

x_value-opt = 'E'.

x_value-sigh = 'BT'

append x_range to r_value.

repeat this for all set of values.

if not x in r_value.

your logic.

endif.

Message was edited by:

I Can Solve It

Message was edited by:

I Can Solve It

[Former Member]

IF NOT

( ( 8000 < x < 8500 ) OR

( 9000 < x < 9500 ) OR

( 10000 < x < 10500 ) OR

( 11000 < x < 11500 ) OR

( 12000 < x < 12500 ) ).

e_flag = 1. "<-----X does not fall in any of the range specified. This is a Error Case.

ENDIF.

Regards,

A.Singh.

[marcelo_ramos1]

Hi,

Try this way.

IF NOT ( INT >= 8000 AND INT <= 8500 ) AND

NOT ( INT >= 10000 AND INT <= 10500 ) AND

NOT ( INT >= 11000 AND INT <= 11500 ) AND

NOT ( INT >= 12000 AND INT <= 12500 ).

...

ENDIF.

Regards.

Marcelo Ramos