simple code help

[Former Member]

Hi,

I have a field value like this

f1 = 12.987

I must show only f1 = 12.9

How dod i do this?

[Former Member]

HI,

data f2 type p decimal 1.

f2 = f1.

write: f2.

Regards

SAB

[Former Member]

declare f1 as type p decimals 1. or else declare f2 and type p decimals 1 and move f1 to f2 and display f2.

Award points if it helps you.

Message was edited by:

Vinni

[Former Member]

I can't change the definition..I have to write some other code

[Former Member]

In that case you can create a local variable as below and pass its value to the original variable afterwards:

data f2 type p decimal 1.

f2 = f1.

f1 = f2.

Here F1 will have value as 12.900

Is that okay?

[Former Member]

You don't have to change the definition of f1. you can declare another variable f2 and can use that.

[Former Member]

hi,

u can also try this..

data f1 type string.

data: one type string.

data: two type string.

data: three type string.

f1 = '12.953'.

split f1 at '.' into one two.

three = two+0(1).

concatenate one '.' three into one.

write: one.

Regards

SAB

[Former Member]

I must even round up the decimal

[Former Member]

You don't have to when you declare your other variable v2 as type p decimals 1. you will achieve what you wanted.

[Former Member]

Hi,

If you want to round use the CEIL function..

<b>Example</b>

DATA: v_p3 TYPE p DECIMALS 3 VALUE '12.987'.

DATA: v_p1 TYPE p DECIMALS 1.

v_p1 = ceil( v_p3 ).

WRITE: / v_p1.

Thanks,

Naren

[Former Member]

Hi,

You can try using in the function module ROUND

Example..

DATA: v_p3 TYPE p DECIMALS 3 VALUE '12.567'.

DATA: v_p1 TYPE p DECIMALS 1.

CALL FUNCTION 'ROUND'

EXPORTING

decimals = 1

input = v_p3

IMPORTING

output = v_p1

EXCEPTIONS

input_invalid = 1

overflow = 2

type_invalid = 3

OTHERS = 4.

WRITE: / v_p1.

THanks,

Naren