scripts

[Former Member]

hi to all,

pplz help me in the issue,

i am having a field 'mhnk-ausdt' it is rundate in dunning

i need mhnk-ausdt + 7th day day like ex

mhnk-ausdt is 14th sep and 7th day of it is 21st sep

how can i achieve this.

thanks in advance

kiran kumar

Message was edited by: kiran kumar

[Former Member]

hi sid

how to use perfrom control command for getting the desired date

tahnks in advance,

kiran kumar

[Former Member]

Use the function module DATE_IN_FUTURE.

You can add 7 days to the date you pass.

[Former Member]

to add 7 days to field 'MHNK-AUSDT' can be done by

MHNK-AUSDT = MHNK-AUSDT + 7.

The above statement will add 7 days to the date. The above statement has to writted in the print program.

If you want to add the 7 days to the date in the form then you have to use PERFORM control command by passing the 'MHNK-AUSDT'.

In SAPSCRIPT:

/: DEFINE &V_DATE&

/: PERFORM GET_DATE IN PROGRAM ZPROG

/: USING &MHNK-AUSDT&

/: CHANGING &V_DATE&

/: ENDPERFORM

Coding of the calling ABAP program:

REPORT ZPROG.

FORM GET_DATE TABLES IN_PAR STUCTURE ITCSY
                     OUT_PAR STRUCTURE ITCSY.
data: l_date like sy-datum.
*-- if the date is in MM/DD/YYYY format


READ TABLE IN_PAR WITH KEY ‘MHNK-AUSDT’.

IF SY-SUBRC = 0.
l_date+0(4) = IN_PAR-VALUE+6(4).
l_date+4(2) = IN_PAR-VALUE+0(2).
l_date+6(2) = IN_PAR-VALUE+3(2).
ENDIF.
l_date = l_date + 7.

READ TABLE OUT_PAR WITH KEY ‘V_DATE’.
IF SY-SUBRC = 0.
  write l_date to OUT_PAR-VALUE.
  MODIFY OUT_PAR INDEX SY-TABIX.
ENDIF.

ENDIF.

[Former Member]

hi sid

how to use perfrom control command for getting the desired date

tahnks in advance,

kiran kumar

[Former Member]

/: DEFINE &V_DATE&

/: PERFORM GET_DATE IN PROGRAM ZPROG

/: USING &MHNK-AUSDT&

/: CHANGING &V_DATE&

/: ENDPERFORM

Coding of the calling ABAP program:

REPORT ZPROG.

FORM GET_DATE TABLES IN_PAR STUCTURE ITCSY

OUT_PAR STRUCTURE ITCSY.

data: l_date like sy-datum.

*-- if the date is in MM/DD/YYYY format

READ TABLE IN_PAR WITH KEY ‘MHNK-AUSDT’.

IF SY-SUBRC = 0.

l_date0(4) = IN_PAR-VALUE6(4).

l_date4(2) = IN_PAR-VALUE0(2).

l_date6(2) = IN_PAR-VALUE3(2).

ENDIF.

l_date = l_date + 7.

READ TABLE OUT_PAR WITH KEY ‘V_DATE’.

IF SY-SUBRC = 0.

write l_date to OUT_PAR-VALUE.

MODIFY OUT_PAR INDEX SY-TABIX.

ENDIF.

ENDIF.

[Former Member]

Hi Kiran,

It is very simple since all date type fields in abap (in tables - type 'DATS', in programs - type d, also sy-datum in system table, etc.) are treated as simple numbers (integers, if u will...).

This means that if u check the value of these fields (in debugger) u will find the date today is 20060914 - this is YYYYMMDD format but it is treated as a number. With numbers u can do arithmetic operations: add, sub, etc.

Now all u have to do is add 7 and get the date u r looking for...

U don't have to check if it went to the next month or year since the system knows to do that. For example: if your field, mhnk-ausdt, has 30th dec 2006 in it, after adding 2 the result will be 1st jan 2007.

The system will calculate 20061230 + 2 and the result is 20070101.

Hope this covers it...

Igal

(Pls reward if it helps)