rounding value.

[Former Member]

PARAMETER: lv_amt type p DECIMALS 2.

data: lv_data type p.

lv_data = lv_amt.

if lv_data > lv_amt.

lv_amt = '0.50'.

lv_amt = lv_data - lv_amt.

else.

lv_amt = '0.50'.

lv_amt = lv_data + lv_amt.

endif.

WRITE lv_amt.

sample code: if I'm entering the value 12.33 then it comes 12.50

12.67 then 13

but i need when im entering the 12.50 then no chanegs same as value 12.50

first 2cases it is okay! for my program.

[Former Member]

Hi,

I did not get you ..

but yuo can check ceil or floor function for same.

Ashutosh

[Former Member]

Hi ..

Thanks for response...

I need that if i give the value 12.33 then its o/p = 12.50 and 12.67 then its o/p = 13 and 12.50 then its o/p 12.50 and 12 then its o/p 12 only i need

based on 0.5 value we can put condtion

[Former Member]

Hello

Your code, but a little modified:

PARAMETER: lv_amt type p DECIMALS 2.

data: lv_data type p,
      d type p decimals 2.

lv_data = lv_amt.
d = frac( lv_amt ).
if lv_data > lv_amt.
  if d > '0.50'.
    lv_amt = lv_data.
  endif.
else.
lv_amt = '0.50'.
lv_amt = lv_data + lv_amt.
endif.

WRITE lv_amt.

[Former Member]

Dear Nagaraju Gaddam,

I hope the below code will help you to fix the issue,

PARAMETER: lv_amt TYPE p DECIMALS 2.

DATA: lv_data TYPE p,
      d TYPE p DECIMALS 2.

lv_data = lv_amt.
d = FRAC( lv_amt ).
IF lv_data > lv_amt.
  IF d > '0.50'.
    lv_amt = lv_data.
  ENDIF.
ELSE.
  IF d EQ 0.
  ELSE.
    lv_amt = '0.50'.
    lv_amt = lv_data + lv_amt.
  ENDIF.
ENDIF.

WRITE lv_amt.

Regards

Harish Kumar