Replace protected spaces in string

[Former Member]

Hi together,

I think I've got a quite easy problem, but no idea how to solve it.

I've got a string for example ' Hello' the spaces are protected ones, represented

in hex as 'A0'.

Using condense to delete the leading spaces has no effect on my string?

Has anyone a hint how to solve this?

King regards

Lars

[Former Member]

Hi,

Try it with string operations.

for example:

w_str = 'Hello '.
w_len = strlen( w_str ).
subtract 2 from w_len.
w_str2 = w_str+0(w_len).

Regards,

Manoj Kumar P

[Former Member]

Try as below

Data : v_space type c value CL_ABAP_CHAR_UTILITIES=>Horizontal_tab.

REPLACE ALL OCCURRENCES OF  v_space in v_string with ' '.
condense v_string NO-GAPS.

hope this helps...

[Former Member]

Thanks your both of your ideas,

but CL_ABAP_CHAR_UTILITIES=>Horizontal_tab.

is represented in hex as '09'.

Kind regards

[Former Member]

Hi together,

I've found a working solution, maybe it's interessting for u.

Data: lv_rep(1) TYPE c.

Data: lv_replace type string.

lv_replace = ' Test'.

CALL METHOD cl_abap_conv_in_ce=>uccp

EXPORTING

uccp = '00A0'

RECEIVING

char = lv_rep.

REPLACE ALL OCCURRENCES OF lv_rep IN lv_replace WITH ' '.

This works.

Kind regards.

Lars