Replace: problem with zeros

[Former Member]

Hi to everybody

I have tihs values

31.800

0.300

2.100

I should to get this

31,800

00,300

02,100

I use REPLACE ALL OCCURRENCES OF '.' IN lt_itob-id1 WITH ',' it is ok

but I get an error if I use REPLACE ALL OCCURRENCES OF space IN lt_itob-id1 WITH '0' .

Could you help me?

Thanks a loto

[Former Member]

Hi

For pdding zeros in the begning use the following:

SHIFT RIGHT <variable> RIGHT DELETING TRAILING SPACE.

And for replacing '.' with ',', i think you will ahve to make use of IF loop and do this operation withn it.

Regards

Gaurav

[kesavadas_thekkillath]

Please be more clear .

[Former Member]

Hi,

I think you can use SHIFT statement as suggested. Press F1 on SHIFT.

[Clemenss]

Hi Georgio,

unable to answer incomplete questions: ID1 is no field of DB view ITOB. Thus you should give the field technical settings here.

Post a few code lines on how you populate the field (Don't worry, CIA knows anyway)..

Then someone can answer your question.

Regards,

Clemens

[Former Member]

Hi ,

if the pattern of the variable in which u r taking value is constant,i.e if there are 3 values after decimal as shown in below code ,you can use below code.

DATA : l_local(6) TYPE c.

l_local = '0.300'.

concatenate '0' l_local into l_local.

REPLACE ALL OCCURRENCES OF '.' IN l_local WITH ',' .

Edited By

Tejaswini Khante

[Former Member]

Hi,

To Replace space with '0' use OVERLAY statement.

DATA: l_val TYPE char6 VALUE '0.300'.

REPLACE ALL OCCURRENCES OF '.' IN l_val WITH ',' .
SHIFT l_val RIGHT DELETING TRAILING space.

OVERLAY l_val WITH '000000'.
WRITE l_val.

Regards,

Farheen