Question on CONCATENATE behavior

[Former Member]

it seems concatenate will add a blank to integer, differs from dealing with string.

is there any rules?

<code>

data l_string type string.

field-SYMBOLS <fs> TYPE any.

ASSIGN l_string to <fs>.

<fs> = 5.

CONCATENATE '{' <fs> '}' INTO l_string.

WRITE: / l_string. " result = l_string = '5 '. CONCATENATE '{' l_string '}' INTO l_string. WRITE: / l_string. " result =

</code>

[Former Member]

it seems concatenate will add a blank to integer, differs from dealing with string.

is there any rules?

<code>

data l_string type string.

field-SYMBOLS <fs> TYPE any.

ASSIGN l_string to <fs>.

<fs> = 5.

CONCATENATE '{' <fs> '}' INTO l_string.

WRITE: / l_string. " result = l_string = '5 '. CONCATENATE '{' l_string '}' INTO l_string. WRITE: / l_string. " result =

</code>

[Former Member]

string will automatically truncate the extra spaces.

declare l_string as like below...

data: l_string(15) type c.

you can see the difference....

[arpit_shah]

hi.

u can use like

CONCATENATE '{' <fs> '}' INTO l_string separated by space.

regards,

Arpit

[Former Member]

actually, i want to eliminate the blank after it. i need instead of , and input is integer rather than string. how could i do?

[i048168]

Hi,

I assigned <fs> = '5'. 5 within inverted commas. Then the result is .

Regards

Vadi

[Former Member]

ok, i think my question is "how to convert integer to string without tailing blanks" then.

my general purpose method is following:

if i_right_operand = 5 (type i), then i will get '5 ', not '5'.

declaration

methods wrap_cond_param

importing

!i_left_operand type fieldname optional

!i_operator type uj_string optional

!i_right_operand type data

returning

value(e_wrapped_param) type uj_string

raising

cx_ujc_exception .

implementation

method wrap_cond_param.

e_wrapped_param = i_right_operand.

" deal with Escape-Characters

replace all occurrences of substring '''' in e_wrapped_param with ''''''.

" wrap Single-Quotation-Mark

concatenate '''' e_wrapped_param '''' into e_wrapped_param.

" wrap NAME OP VALUE

if i_left_operand is not initial and i_operator is not initial.

concatenate i_left_operand i_operator e_wrapped_param into e_wrapped_param separated by space.

endif.

endmethod.

Edited by: Davin Wang on Jan 3, 2008 4:30 PM

[Former Member]

Friend,

Try this...

CONCATENATE '{' <fs> '}' INTO l_string.

CONDENSE l_string no-GAPS.

WRITE: / l_string. " result =

[Former Member]

thanks Ramu,

CONDENSE is very helpful for integer, but it doesn't work with string, on the opposite.

is there a ALL-IN-ONE solution?

data l_string type string.

field-SYMBOLS <fs> TYPE any.

ASSIGN l_string to <fs>.

<fs> = 5.

CONCATENATE '{' <fs> '}' INTO l_string SEPARATED BY space.

CONDENSE l_string no-GAPS.

WRITE: / l_string. " result = expected

l_string = '2 6'.

CONCATENATE '{' l_string '}' INTO l_string.

CONDENSE l_string no-GAPS.

WRITE: / l_string. " result = expected {2 6} here

Edited by: Davin Wang on Jan 3, 2008 4:38 PM

[Former Member]

Friend,

Try this...

data: len type i.

CONCATENATE '{' <fs> INTO l_string.

len = strlen( l_string ) - 1.

l_string = l_string+0(len).

CONCATENATE l_string '}' INTO l_string.

write:/ l_string.