2015 Jun 19 3:04 PM
Hi All, i am facing performance issue with following select query. i have 5000 knumh values and i just want to check atleast one knumh exist in konv table or not. Can anyone help me to improve below select SELECT * FROM konv INTO TABLE lt_konv up to 1 row where knumh in lr_knumh. Note : No of entries(from Se11) in KONV table is very huge. getting runtime error after 90min. Regards, Praveen
Hi All, i am facing performance issue with following select query. i have 5000 knumh values and i just want to check atleast one knumh exist in konv table or not. Can anyone help me to improve below select SELECT * FROM konv INTO TABLE lt_konv up to 1 row where knumh in lr_knumh. Note : No of entries(from Se11) in KONV table is very huge. getting runtime error after 90min. Regards, Praveen
2015 Jun 19 3:12 PM
Hi Praveen,
If your requirement is just to check if at least one entry exits then do the below piece.
Hope you are already removing duplicates from your range table
SORT LR_KNUMH BY LOW.
DELETE ADJACENT DUPLICATES FROM LR_KNUMH COMPARING LOW.
SELECT COUNT( * ) UP TO 1 ROW
FROM KONV
WHERE KNUMH IN LR_KNUMH.
The above statement does not need any container to hold select data. If it finds even 1 entry, your sy-subrc eq 0.
Regards,
Raju
2015 Jun 19 3:21 PM
Why you are querying via KNUMH? KONV is cluster table. Only good way to select from it via KNUMV.
R
2015 Jun 19 3:49 PM
can you explain your requirement? may be we can suggest an alternate solution.
KONV is a cluster table and you should avoid reading from it without using all the primary keys.
2015 Jun 21 5:45 AM
Hello,
This advice won't help directly, but you should use Select....EndSelect when you want to fetch a single record and you do not have primary key in the where clause else go for Select Single.
BR.
2015 Jun 22 7:41 AM
Hi,
ur statement should only last a few sec. you can try selecting via se16.your programm should take the same time.
for selecting single value, i would use "select single"-statement.
im not very common with the cluster tables. But maybe a new index can help?
regards
Stefan Seeburger.
2015 Jun 22 7:50 AM
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