2008 Mar 25 9:52 AM
Hi
I have 5 internal tables. I want to move all the records into single internal table. All 5 internal tables (1 header table and 4 item table) are in different structure. If any one have sample code for this please post the logic for the same.
Regards
Ravi
2008 Mar 25 9:56 AM
Hi Without knowing the fields of the 5 internal tables there is no way we can a logic for your problem.
Normally it is done like this.
Loop at the header table.
read from the item1 with key field1 = headerfield1.
read from the item2 with key field1 = headerfield2.
read from the item3 with key field1 = headerfield3.
read from the item4 with key field1 = headerfield4.
store the values in a work area of the final structure.
append all the values into the final structure.
endloop.
Hi
I have 5 internal tables. I want to move all the records into single internal table. All 5 internal tables (1 header table and 4 item table) are in different structure. If any one have sample code for this please post the logic for the same.
Regards
Ravi
2008 Mar 25 9:56 AM
Hi Without knowing the fields of the 5 internal tables there is no way we can a logic for your problem.
Normally it is done like this.
Loop at the header table.
read from the item1 with key field1 = headerfield1.
read from the item2 with key field1 = headerfield2.
read from the item3 with key field1 = headerfield3.
read from the item4 with key field1 = headerfield4.
store the values in a work area of the final structure.
append all the values into the final structure.
endloop.
2008 Mar 25 9:57 AM
Hi,
if all internal tables of same structure you can easily move all values to one internal table,if it has different structure it is little difficult ,you have to move only by field to field....
Regards,
V.Balaji
Reward if usefull
2008 Mar 25 9:58 AM
Hi
loop at one item table make it as final type
read table2 based on loop
read table3based on loop
so on
finally use modify transrporting to get all the fields into one table
regards
Shiva
2008 Mar 25 9:58 AM
Hi,
U cannot merge internal Tables of different structures .
Only way to create a structure with all the header and Item fields .
using the LOOP statement move the contents and append it into a the Final Internal Table .
Regards,
Balakumar.G
Reward Points if helpful.
2008 Mar 25 10:01 AM
HI,
Try this formate.
LOOP AT mattab.
SELECT SINGLE * FROM mara WHERE matnr = mattab-matnr.
IF sy-subrc = 0.
*** mara
it_final-matnr = mara-matnr.
it_final-mtart = mara-mtart.
it_final-meins = mara-meins.
it_final-matkl = mara-matkl.
it_final-brgew = mara-brgew.
it_final-ntgew = mara-ntgew.
it_final-gewei = mara-gewei.
it_final-zeinr = mara-zeinr.
it_final-ekwsl = mara-ekwsl.
it_final-iprkz = mara-iprkz.
***This is for Qulity
it_qulity-matnr = mara-matnr.
it_qulity-qmpur = mara-qmpur.
***This is for Accounting
it_act-matnr = mara-matnr.
***This is for Sales
it_sales-matnr = mara-matnr.
it_sales-tragr = mara-tragr.
it_sales-taxkm = mara-taklv.
ENDIF.
append it_final.
clear it_final.
endloop.REgards,
S.Nehru
2008 Mar 25 10:07 AM
Hi
There is no link(Key fields) between all the 5 internal tables.
i want to print like this.
Header
Batch Header
Item1
item2
item3
batch header
item1
item2
item3.
This is a IFILE Requirment for INDIAN BANKS to print cheques..
Regards
Ravi
2008 Mar 25 10:04 AM
Build a final internal table with all required fields based on Header and 5 item internal table.
then move corresponding data as below...........
loop at head.
move-corresponding head to final.
read item1 with key item1-field = head-field.
if sy-subrc eq 0.
move-corresponding item1 to final.
endif.
read item2 with key item2-field = head-field.
if sy-subrc eq 0.
move-corresponding item2 to final.
endif.
read item3 with key item3-field = head-field.
if sy-subrc eq 0.
move-corresponding item3 to final.
endif.
read item4 with key item4-field = head-field.
if sy-subrc eq 0.
move-corresponding item4 to final.
endif.
reward if useful............
append final.
endloop.
2008 Mar 25 10:04 AM
hi,
report ztest.
tables:pa0002,pa0008,pa0021,pa0041.
data: begin of itab occurs 0,
pernr like pa0002-pernr,
vorna like pa0002-vorna,
nachn like pa0002-nachn,
end of itab.
data: begin of itab1 occurs 0,
pernr like pa0008-pernr,
begda like pa0008-begda,
stvor like pa0008-stvor,
ansal like pa0008-ansal,
end of itab1.
data :begin of itab2 occurs 0,
pernr like pa0021-pernr,
favor like pa0021-favor,
fanam like pa0021-fanam,
end of itab2.
data:begin of itab3 occurs 0,
pernr like pa0041-pernr,
dar01 like pa0041-dar01,
dat01 like pa0041-dat01,
end of itab3.
data:begin of final occurs 0,
pernr like pa0002-pernr,
vorna like pa0002-vorna,
nachn like pa0002-nachn,
begda like pa0008-begda,
stvor like pa0008-stvor,
ansal like pa0008-ansal,
favor like pa0021-favor,
fanam like pa0021-fanam,
dar01 like pa0041-dar01,
dat01 like pa0041-dat01,
end of final.
select-options:s_pernr for pa0002-pernr.
select pernr
vorna
nachn
from pa0002
into table itab
where pernr in s_pernr.
select pernr
begda
stvor
ansal
from pa0008
into table itab1
for all entries in itab
where pernr = itab-pernr.
select pernr
favor
fanam
from pa0021
into table itab2
for all entries in itab1
where pernr = itab1-pernr.
select pernr
dar01
dat01
from pa0041
into table itab3
for all entries in itab2
where pernr = itab2-pernr.
loop at itab.
final-pernr = itab-pernr.
final-vorna = itab-vorna.
final-nachn = itab-nachn.
read table itab1 with key pernr = itab-pernr.
final-begda = itab1-begda.
final-stvor = itab1-stvor.
final-ansal = itab1-ansal.
read table itab2 with key pernr = itab1-pernr.
final-favor = itab2-favor.
final-fanam = itab2-fanam.
read table itab3 with key pernr = itab2-pernr.
final-dar01 = itab3-dar01 .
final-dat01 = itab3-dat01.
append final.
clear final.
endloop.
loop at final.
write:final-pernr ,
final-vorna ,
final-nachn ,
final-begda ,
final-stvor ,
final-ansal ,
final-favor ,
final-fanam ,
final-dar01 ,
final-dat01 .
endloop.
regards,
venkat.
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