logic

[Former Member]

pls tell how many times this loop will executes...

n=2.

do n times.

write n.

n=n+1.

enddo.

[Former Member]

Hi,

This is a infinite loop.

To stop the loop give condition like

do n times.

write n.

n=n+1.

<b>If n = 20.

EXIT.

Endif.</b>

enddo.

Reward if helpful.

[Former Member]

this will execute only 2 times, just tested that

before the DO loop value of n is 2 , so it will loop only 2 times..

Output will be 2 and 3

[Former Member]

2 times ur output will be 2 & 3

[Former Member]

It is an infinite loop because you are telling it to execute 'n' number of times, but you are incrementing 'n' within each loop pass, so it will just go on and on

I stand corrected, it does only execute twice

Message was edited by:

showthousand

[Former Member]

hi

Whats is type for n?.

In its integer then it will execute infinity times.

because ur adding n = N + 1. So it will goto short dumb.

Regards

Ravi

[Former Member]

Hi Ramna,

This will execute<b> only 2 times</b> and the output will be

2

3

It will always consider the value of <b>N times</b> when the DO...ENDDO before starting up of execution but it wont consider the values even it is updated in the DO...ENDDO.

Thanks,

Vinay

[Former Member]

Hi Ramna,

Actual it is not an infinite loop but you made it as infinite loop.

Reason:

Your looping on n. initial it n has value 2 .

once the loop encounterd then you have incremented n. so it mean n beacme 3. so the loop has to turn 3 times now. this process will continue in this way so it became infinite loop

Regards,

Lisa

[Former Member]

the do control structure does not accept any change of the value n with

in the loop.if n contains a value less than or equal to zero the statement block will not be executed..so ur out put will be 2 and 3 though its type is numc or interger or a if float 2.0000000e00 3.0000000e00