‎2007 Apr 20 1:02 PM
Hi Gurus!!
I have created a lock object to a z-table. The lock mode is E.
After this:
call function 'ENQUEUE_EZTABLA'
exporting
mode_ztabla = 'E'
client = sy-mandt
key1 = 'HOLA'
key2 = 'ADIOS'
x_key1 = ' '
x_key2 = ' '
_scope = '2'
_wait = 'E'
_collect = ' '
exceptions
foreign_lock = 1
system_failure = 2
others = 3.
I can see the entrie on the table with key1 = 'HOLA and key2 = 'ADIOS' on SE16 transaction with 2 differents users, moreover I have locked with USER1 and I have modified the table with user 2.
Is normal this?
Helpful answers will be rewarded,
Manuel.
‎2007 Apr 20 1:08 PM
Are you modifying the table at the same time with user1 and user2.
If it not at the same time then it should not be a problem.
‎2007 Apr 20 1:08 PM
Are you modifying the table at the same time with user1 and user2.
If it not at the same time then it should not be a problem.
‎2007 Apr 20 1:20 PM
Hi Chandrasekhar,
I know what you say, I have just modified with the user2.
I have tried to open the maintenance dialog of ztable on sm30 with user2 and modify on the report where I call function ENQUEUE, and I can modify without problems. (I hope I explain the situation correctly).
Do you know another way to test this?
Thanks and regards,
Manuel.