last characters

[Former Member]

hi sap,

i have a field - objnr -ISTR030000001000007

i need to take out the first 12 characters and keep the last 7 characters.

so how can i do it can you pls tell me

regards,

laya.

[I355602]

Hi,

You can use the offset technique.

Refer:

data : objnr type objnr. "length for objnr is 18

objnr = 'STR030000001000007'.

data : v_str(10) type c.

v_str = objnr+11(7).

write : v_str, objnr.

Regards,

Tarun

[Former Member]

Use offsets.

data : v_str1 type string value 'ISTR030000001000007' ,
         v_str2 type(12) type c,
         v_str3 type(7) type c.

v_str2 = v_str1+0(12).
v_str3= vstr1+13(7).

Write: v_str2, v_str3.

Thanks

[Former Member]

Hi,

Try this Way..

DATA : l_len TYPE i.
DATA: l_value(7) TYPE c.
DATA l_objnr TYPE CHAR30.
l_objnr = 'ISTR030000001000007'.
l_len = STRLEN( l_objnr ).

l_len = l_len - 7 .

l_value = l_objnr+l_len(7).
WRITE l_value.

[Former Member]

Hi,

For this particular case use:

data: v_objnr(7) type c.

v_objnr = objnr+12(7).

Regards.

[Former Member]

Hi,

This is simple, hope below code snippet help you out:

data:objnr(19) value 'ISTR030000001000007',
       val(7) tyep c.
val = objnr+12(7).

write:/ val.

Pooja

[Former Member]

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