internal table

[Former Member]

hi,

my internal table is like this,

having 3 fields

number, material, quantiy values are

1,mat1,10

2,mat2,20

3,mat1,30

4,mat3,40

and i want o/p as mat1=30

mat2= 20,mat3=40

pls help me.

[Former Member]

If you are sure with your table format you can do this way:

<field-symbols>: <f_fs1> type data,

<f_fs2> type any.

data: l_text type string.

loop at itab into <f_fs1>.

do 3 times.

ASSIGN COMPONENT sy-index OF STRUCTURE <f_fs1> TO <f_fs2>.

if sy-index eq 1.

l_text = <f_fs2>

else.

concatenate <f_fs2> l_text into l_text.

enddo.

endloop.

regards,

SV.

[Former Member]

Hi,

Sort itab by matnr.

Delete adjacent duplicates from itab comparing matnr.

[Former Member]

Hi ,

U can use append sorted by statement.

and define internal table size is occurs 3.

it will append internal table upto 3 records only.

and mentioned the sort field by last field i mean ur number field (10,20,30)

then u will get correct answer.

try with this.

mean while i try and send you code.

thanks,

surendra Babu vemula

[karol_seman]

Hi Venkat,

to get collected values check the key word "COLLECT".

To remove duplicates sort the table by field you want to eliminate duplicates and use DELETE ADJACENT DUPLICATES FROM <itab> comparing <f1> ... <fn>

Regards,

Karol

[Former Member]

Hi venkat,

you use this code and try you will get exact code what u r expecting.

DATA: BEGIN OF itab OCCURS 3,

f1 TYPE i,

f2(10) TYPE c,

f3 TYPE i,

END OF itab.

*

itab-f1 = 1.

itab-f2 = 'MAT1'.

itab-f3 = 10.

APPEND itab.

CLEAR itab.

*

itab-f1 = 2.

itab-f2 = 'MAT2'.

itab-f3 = 20.

APPEND itab.

CLEAR itab.

*

itab-f1 = 3.

itab-f2 = 'MAT1'.

itab-f3 = 30.

APPEND itab.

CLEAR itab.

*

itab-f1 = 4.

itab-f2 = 'MAT3'.

itab-f3 = 40.

APPEND itab.

CLEAR itab.

*

SORT itab BY f2 f3 DESCENDING.

DELETE ADJACENT DUPLICATES FROM itab COMPARING f2.

*

LOOP AT itab.

WRITE: / itab-f2, '=', itab-f3.

ENDLOOP.

output:

MAT1 = 30

MAT2 = 20

MAT3 = 40

thanks,

surendra babu vemula