internal table help needed

[Former Member]

Hi ,

I have one problem in report.

I have X table having fields f1, f2...............f10.

data: lt_tab "internal table

ls_tab "WA

for field f1 i got multiple entries in lt_fun by function module.

Now i have condition like

ls_tab-f2 = .....

ls_tab-f3 = ......

append ls_tab to lt_tab.

calling FM

by passing f1 i got multiple entries in lt_fun.

*suppose lt_fun having 2 records.

loop at lt_fun from ls_fun .

lv_tabix = sy-tabix.

gs_tab-f4 = ls_fun-f4.

gs_tab-f5 = ls_fun-f5.

modify lt_tab from ls_tab index lv_tabix transporting f3 f4.

endloop.

Is the above mentioned logic is fine.?

I am assuming output like

X

f1 f2 f3 f4 f5

1 a a1 a2 a3

b2 b3

c3 c3

Pls let me know asap.

[Former Member]

Hi NEHA ,

Logic is fine .

But my question is for f1 if you get two entries in table lt_fun .then how do you decide that it will in field F4 and f5 .

[Former Member]

No dinesh it is not looking like what i wanted to write.

Actually

X

f1 f2 f3 f4 f5

1 a1 a1 a2 a3

b2 b3

[Former Member]

OK, ket me see if this is what you wanted.

loop at itab into wa.

loop at lt_fun into ls_fun where f2 = wa-f2.

move-correspoding wa to ls_final.

ls_final-f2 = ls_fun-f2.

ls_final-f3 = ls_fun-f3.

append ls_final to lt_final.

clear ls_final.

endloop.

endloop.

lt_final will have the final internal table.

Regards,

ravi

[Former Member]

Hi,

I am assiuming the output is like this. Due to some setting problem it was changed.

X

f1 f2 f3 f4 f5

1 a a1 a2 a3

o o o b2 b3

o o o c2 c3

Pls assume that o means no value.

[Former Member]

can u give me the code what u written