how to find a string into another string

[Former Member]

Hi,

I'm trying to give a validation on the input file name which is given below.I dont want to hard code the path.when i'm giving F4 help it should pick only

' C.028 Project Plan balances_DMTHMPLAN ' file .if the file having different name is picked than it should give an error.

I'm trying to do this via this code.

Can anyone help me out.

IF P_FILE NP ' C.028 Project Plan balances_DMTHMPLAN' .

IF SY-FDPOS = 1.

MESSAGE E000 WITH TEXT-001 .

ENDIF.

ENDIF.

[Former Member]

Use CS keyword and check.

Means contains string

[Former Member]

Hi,

SEARCH f FOR g.

regards

Nicole

[Former Member]

hi,

do this way ..

IF P_FILE NS ' C.028 Project Plan balances_DMTHMPLAN' .
   MESSAGE E000 WITH TEXT-001 .
ENDIF. 

[Former Member]

Hi Dheeraj,

You can try using CS (Contains String) or CP (Contains Pattern ). But be specific , as it is case-sensitive.

Try using :

IF P_FILE CS ' C.028 Project Plan balances_DMTHMPLAN' .

or

IF P_FILE CP ' C.028 Project Plan balances_DMTHMPLAN' .

Choose the kind of syntax as per your requirement.

Hope this is helpful to you. If you need further information, revert

back.

Reward all the helpful answers.

Regards

Nagaraj T

[Former Member]

HI,

use find keyword.

FIND 'C.028 Project Plan balances_DMTHMPLAN' in file.
IF subrc <> 0.
  MESSAGE e000(zmsg_tab) with 'error'.
ENDIF.

rgds,

bharat.

[Former Member]

Hi,

You can use this code with little bit modifications as of ur requirements.

PARAMETERS: P_FILE TYPE RLGRAP-FILENAME.

AT SELECTION-SCREEN ON VALUE-REQUEST FOR P_FILE.

CALL FUNCTION 'F4_FILENAME'

EXPORTING

PROGRAM_NAME = SYST-CPROG

DYNPRO_NUMBER = SYST-DYNNR

FIELD_NAME = ' '

IMPORTING

FILE_NAME = P_FILE.

IF P_FILE NE 'C.028 Project Plan balances_DMTHMPLAN'.

MESSAGE i000(Z50871MSG) WITH 'error' .

ENDIF.

Regards

Sandeep Reddy

[Former Member]

Thanks a lot