How to convert string to date format?

[Former Member]

Hi All,

String is in following format: 2006-12-07 i.e yyyy-mm-dd

I want it in 07.12.2006 date format.

which function module should i used to convert it?

Regards,

Nilima

[Former Member]

Hi All,

String is in following format: 2006-12-07 i.e yyyy-mm-dd

I want it in 07.12.2006 date format.

which function module should i used to convert it?

Regards,

Nilima

[gopi_narendra]

Use the FM : CONVERSION_EXIT_IDATE_INPUT to convert date to Date format.

Regards

Gopi

[Former Member]

Hi Nilima,

lv_date = 2006-12-07

use

concatenate lv_date+8(2)

'.'

lv_date+5(2)

'.'

lv_date+0(4)

into lv_date_new

Regards

Arun

[Former Member]

Hi,

Try like this:

DATA: ZTEMP(10),zdd(3),zmmm(3),zyyyy(4),zfinal(12), v_date(10) type c.

CLEAR: ZTEMP, ZDD, ZMMM, ZYYYY.

v_date = '2007-08-07'. "yyyy-mm-dd

zyyyy = v_date+0(4).

zmmm = v_date+5(2).

zdd = v_date+8(2).

concatenate zdd '.' zmmm '.' zyyyy into ztemp.

write:/ v_date,

/ ztemp.

Regards,

Bhaskar

[Former Member]

an other way to do this :

Code
DATA : ld_text(20) TYPE c, ld_date TYPE datum. ld_text = '2006-12-07'. REPLACE ALL OCCURENCES OF '-' IN ld_text WITH ''. WRITE ld_text TO ld_date. WRITE ld_date.

[former_member386202]

Hi,

I dont think there will be FM for this. Try Like this

data: lv_formatdate(10) type c,

         lv_date type char10.

lv_date = 2006-12-07.

  var1 = lv_date+(4).

  var2 = lv_date+5(2).

  var3 = lv_date+8(2).

concatenate var3 var2 var1 into lv_formatdate separated by '.'.

Regards,

Prashant