->* operator

[Former Member]

Hello,

Im reading the documentation on ->* operator, and dont really understand how it works, can any body tell me its functionality?

Thanks

Gabriel P.

[Former Member]

Basically it is a deferencing operator. It is used for refering an anonymus object of any type.

Check this piece of code

DATA:   gt_dyn_table TYPE REF TO data,
        gs_dyn_line  TYPE REF TO data.

FIELD-SYMBOLS: <fs_quota>   TYPE STANDARD TABLE,
               <fs_amount>,
               <fs_quota_wa>.

*Create dynamic internal table
  CALL METHOD cl_alv_table_create=>create_dynamic_table
               EXPORTING
                  it_fieldcatalog = gt_fldcat
               IMPORTING
                  ep_table        = gt_dyn_table.

  ASSIGN gt_dyn_table->* TO <fs_quota>.

  CREATE DATA gs_dyn_line LIKE LINE OF <fs_quota>.
  ASSIGN gs_dyn_line->* TO <fs_quota_wa>.

Thanks,

Message was edited by: Naren Somen

[Former Member]

What it does, it takes the underlying DATA object from a dynamically created a element, and assigns that to the data element. Other wise there is no way dealing with the dynamically created object.

Regards,

Ravi

[Former Member]

Hi,

CALL METHOD cl_alv_table_create=>create_dynamic_table
EXPORTING
it_fieldcatalog = t_fieldcat
IMPORTING
ep_table = r_dyn_table
EXCEPTIONS
generate_subpool_dir_full = 1
OTHERS = 2.

IF sy-subrc <> 0.
MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
ENDIF.

* Get access to new table using field symbol.

ASSIGN r_dyn_table->* TO <t_dyn_table>.
* Create work area for new table.

CREATE DATA r_wa_dyn_table LIKE LINE OF <t_dyn_table>.

* Get access to new work area using field symbol.

ASSIGN r_wa_dyn_table->* TO <wa_dyn_table>.

Regards

Vijay