Finding the word in String

[Former Member]

Dear All,

I have a requirement i.e I need to search for a particular word in a string as a condition. I can use the Offsetting but then thing is then word can be at any place in the string where we cannot use offsetting i think so.

Wat is the syntax to handle such a requirement.

Please give any sample code if possible.

Thanks

NSK

Edited by: shashikanth naram on Jun 4, 2009 12:11 PM

[Former Member]

Hi,

You can use FIND statement.

Press F1 on FIND for examples

Regards

[GauthamV]

Plz SEARCH in SCN before posting.

[Former Member]

hi,

data: str1(20) value 'the whole string', str2(5).
if str1 CS str2.
"found word from str2 string....
else
endif.

regards,darek

[Former Member]

Hi,

To find a particulat string u can use this example coding,

if itab-field1 CA 'ABCDEFGHIJKLMONQRSTUVWXYZ0123456789+-*/$@^&()<>&~.!'.
replace all occurrences of '#' in itab-kverm1 with space    "any field which you want to select
write: /5 itab-field1
endif.
endloop.
or 

if itab-field1 CO '*'.
replace all occurrences of '*' in itab-field1 with space    "any field which you want to select
write: /5 itab-field1
endif.
endloop.

regards,

Nikhil.

[Former Member]

Cant you use:

IF string CS word

ENDIF.

Can you please explain ur requirmenet more clearly?

[Former Member]

Hi,

Refer:

Regards

Sumana

[Former Member]

Hi,

This piece of code might help you out.

REPORT  ZNIT_REPORT1.

data: str1 type string value 'Hello!!! this is nitesh',
      word(10) value 'nitesh'.
if str1 CS word.
write 'word is there'.
else.
 write 'word is not there'. 
endif.

Thanks.

Nitesh

[Former Member]

use 'CS' operator.

or you can use 'FIND' also .

use f1 help for more documentation and use of both.

[venkat_o]

Hello Shashikanth, Here is the sample program which works fine.

REPORT ztest_notepad.
DATA:str_data TYPE string VALUE 'Venkat is a good guy'.

IF str_data CS 'good'.
  WRITE str_data.
ELSE.
  WRITE 'No'.
ENDIF.

Thanks

[Former Member]

try this code...

data: l_str type string.

data: l_str1 type string.

data: l_str2 type string.

l_str = 'Account determination for payment reference401'.

if l_str+43(1) NE ''.

l_str1 = l_str+0(43).

l_str2 = l_str+43(3).

concatenate l_str1 l_str2 into l_str1 separated by space.

endif.