Error : Data type incompatible

[Former Member]

Hi gurus,

The following is my code:

REPORT zssppgmm1.

DATA: l type c,

t type c,

done type c.

PARAMETERS p(25) DEFAULT ' Vendor Number'.

WHILE done = ' '

VARY l FROM p0 NEXT p1

VARY t FROM p24 NEXT p23.

IF l = ' ' AND t = ' '.

l = t = '-'.

ELSE.

done = 'X'.

ENDIF.

ENDWHILE.

WRITE: / p.

if i execute it, i get the following error msg. how to resolve it

Error: "P" and "L' are type-incompatible.

Thanks and regards,

Suresh

Edited by: Suresh S on Oct 11, 2008 9:41 AM

Edited by: Suresh S on Oct 11, 2008 9:41 AM

[naveen_inuganti2]

Hi...

P is CHAR -25

L is CHAR 1

Make them as same techical properties.

Thanks,

Naveen.I

[Former Member]

Suresh,

try this:

Declare one Var ZZ(25) type C.

and then use this for Parameter PA type ZZ .

Regards..

[Former Member]

hi try this one

DATA: l(25) type c,
t type c,
done type c.

PARAMETERS p like l DEFAULT ' Vendor Number'.

[Former Member]

try THIS:

DATA: L TYPE C,

T TYPE C,

DONE TYPE C.

PARAMETERS: P(25) TYPE C DEFAULT 'Vendor Number'.

WHILE DONE IS INITIAL

VARY L FROM P1(1) NEXT P2(1) RANGE P

VARY T FROM P24(1) NEXT P23(1) RANGE P.

IF L = ' ' AND T = ' '.

L = T = '-'.

ELSE.

DONE = 'X'.

ENDIF.

ENDWHILE.

WRITE: / P.

ERROR WAS DUE TO SIZE INCOMPATIBILITY BETWEEN P AND L

[Former Member]

From what i understand, u might be trying to do this

DATA: L TYPE C,

T TYPE C,

Z(2) TYPE N.

PARAMETERS: P(25) TYPE C DEFAULT 'Vendor Number'.

Z = STRLEN( P ).

WHILE Z > 0

VARY L FROM P0(1) NEXT P1(1) RANGE P.

IF L = ' '.

L = '-'.

ENDIF.

Z = Z - 1.

ENDWHILE.

WRITE: / P.

[Former Member]

Hi Amit Gupta,

Your answer was helpful, but with some logical errors which i have corrected myself. But that was a helpful answers.