Default date format

[Former Member]

Hi,

I want to get default date format for user.

I want to convert a text for example '01.01.2008' to default date format (YYYYMMJJ or JJMMYYYY in depend of user).

Thanks in advance.

[Former Member]

Hi,

Use the FM

CONVERT_DATE_TO_INTERN_FORMAT

Regards

Lekha

[Former Member]

select the DATFM from USR01 table where bname = username.

data element is XUDATFM for datfm .select the fixed value from data element and choose the date format

[Former Member]

CALL FUNCTION 'CONVERT_DATE_TO_INTERN_FORMAT'

EXPORTING

DATUM = '12.02.2001'

DTYPE = 'DATS'

• IMPORTING

• ERROR =

IDATE = lv_date

• MESSG =

• MSGLN =

[Former Member]

Hi,

I hope this will help you,

HRGPBS_HESA_DATE_FORMAT

Regards,

Harish

[Former Member]

Hi,

Use FM CONVERT_DATE_TO_INTERNAL.

Regards,

Raju.

[Former Member]

hii

default format of date is yyyymmdd..so for that you can use FM

CONVERT_DATE_TO_INTERNAL

and for ddmmyyyy for mat you can use logic like below

data:wa_date like sy-datum,

wa_dt(10) type c.

Concatenate wa_date +6(2)wa_date +4(2) wa_date +0(4) into wa_dt.

result = wa_dt

regards

twinkal

[Former Member]

HI,

check with the following FM.

SLS_MISC_GET_USER_FORMAT

[Former Member]

Simo,

for getting default date from user:

use FM DATUMSAUFBEREITUNG.

data: idate TYPE sy-datum,
          tdat8 type string.
 idate              = <your date>
 CALL FUNCTION 'DATUMSAUFBEREITUNG'
     EXPORTING
       IDATE                 = idate
     IMPORTING
        TDAT8                 = tdat8"user's default date formate
    EXCEPTIONS
       DATFM_UNGUELTIG       = 1
       DATUM_UNGUELTIG       = 2
       OTHERS                = 3.

Amit.

[Former Member]

There's a problem with this functions. When i give a different date format in import parameter --> error...

That what i want to do:

I have a text for example '31.08.2008'. I want to convert it the format date of user. If 'YYYYMMJJ' ---> 20080831 and if 'JJMMYYYY' ---> 31082008 etc......

[Former Member]

Simo,

preriquiste of this FM is that , you must change all date before passing in YYYYMMDD formate which comes in idate ,and pass it to FM.you will get user format date .dont worry about user formate , FM would take care of it.

[Former Member]

Look Amit, please test it:

1- Change your default format date: Goto System -> user profile -> Own data and click on Defaults and change date format 'YYYY-MM-DD'

2- MF: 'DATUMSAUFBEREITUNG' with IDATE = '31082008'.

[Former Member]

You tested Amit?

Error because the format in not good

[Former Member]

The goal is to use MF 'SD_DATETIME_DIFFERENCE' because in import parameter (date1 and date2) we must use a default format date

[Former Member]

Simo,

look this piece of code.

data: idate TYPE sy-datum,
          tdat8 type string.
  LOOP AT it_excel.
idate              = p_budat.
    CALL FUNCTION 'DATUMSAUFBEREITUNG'
     EXPORTING
*       FLAGM                 = ' '
*       FLAGW                 = ' '
       IDATE                 = idate
*       IMONT                 = ' '
*       IWEEK                 = ' '
     IMPORTING
*       MDAT4                 =
*       MDAT6                 =
*       TDAT4                 =
*       TDAT6                 =
        TDAT8                 = tdat8
*       WDAT4                 =
*       WDAT6                 =
*     EXCEPTIONS
*       DATFM_UNGUELTIG       = 1
*       DATUM_UNGUELTIG       = 2
*       OTHERS                = 3
              .
    IF sy-subrc <> 0.
* MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
*         WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
    ENDIF.
      it_excel-budat_004 = tdat8.
MODIFY it_excel.
    CLEAR it_excel.
  ENDLOOP.

where p_budat is parameter with type budat.

it werk fine for me in BDC.where i suppose to put a posting date according to user format only.

Amit.

[Former Member]

My first value is char(10) not date not parameter.

data: v_data(10).

v_data = '31.08.2008' for example

My question is how can i do for converting this value on default date format for user?

[Pramanan]

hi,

data: wa type string.

data: w_date type string.

wa = '01.11.2008'.

data:wa_year type char4.

data: wa_month type char2.

data: wa_date type char2.

replace all occurrences of '.' in wa with space.

wa_year = wa+4(4).

wa_month = wa+2(2).

wa_date = wa+0(2).

concatenate wa_year wa_month wa_date into w_date.

Write:/ w_date.

This will exaclty print your desired output.

[Former Member]

Hi,

for this you can directly move the value of type sy-datum to type d and pass the value.

DATA:
  w_date TYPE d.
  w_date = sy-datum. " move value
  write: w_date.

Regards

Adil

[Former Member]

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