date

[Former Member]

How to subtract days from date?

[Former Member]

parameters: p1 type i.

data: d2 like sy-datum,

d3 like sy-datum.

p1 = p1 * ( - 1 ).

d2 = sy-datum.

CALL FUNCTION 'CALCULATE_DATE'

EXPORTING

DAYS = p1

MONTHS = '0'

START_DATE = d2

IMPORTING

RESULT_DATE = d3 .

write d3.

[Former Member]

data: date like sy-datum,
date1 like sy-datum.

date = sy-datum.

CALL FUNCTION 'RP_CALC_DATE_IN_INTERVAL'
EXPORTING
date = date
days = 03
months = 00 
SIGNUM = '-' 
years = 00
IMPORTING
CALC_DATE = date1. " new date


write:/ 'new date', date1.

[Former Member]

Execute the code

parameters: date like sy-datum.

data: date1 like sy-datum.


CALL FUNCTION 'RP_CALC_DATE_IN_INTERVAL'
  EXPORTING
    date            = date
    days            = 15       "days substracted 
    months          = 00
   SIGNUM           = '-' "to substract and + to add 
    years           = 00
 IMPORTING
   CALC_DATE       = date1. " new date


write:/ 'new date',  date1.

regards,

vijay.

[Former Member]

if it is yest date.. then it is

data: l_date like sy-datum.

l_date = sydatum - 1

Message was edited by:

Manjunath Radha Krishna Murthy

[Former Member]

if it is yest date.. then it is

data: l_date like sy-datum.

l_date = sydatum - 1