date difference in days

[Former Member]

is there any function module to find the difference between two dates , i want the result to be displayed in days.

eg : days = 01.01.2006 - 01.01.2005

days : 365

Regards

Purshoth

[anversha_s]

hi,

data: dat1 type sy-datum.
data: dat2 type sy-datum.
data: days like P0347-SCRDD.
 
dat1 = '20051212'.
 
dat2 = '20061212'.
 
 
CALL FUNCTION 'HR_HK_DIFF_BT_2_DATES'
  EXPORTING
    DATE1                         = dat2
    DATE2                         = dat1
   OUTPUT_FORMAT                 = '02'
 IMPORTING
 
  DAYS                          = days          .
 
 
Write:/ days.

Rgds

Anver

[Former Member]

Use FM -

DAYS_BETWEEN_TWO_DATES

[Former Member]

Hi,

you can simle calculate like this:

DATA: date like sy-datum.

data: days type i.

*

date = sy-datum - 100.

*

days = sy-datum - date.

*

write: date, sy-datum, days.

regards, Dieter

[Former Member]

hI pURUSHOTTAM,

U can refer to following FMs to get the diffrence betwwn the dates as well as time in addition.

1. ' /SDF/CMO_DATETIME_DIFFERENCE ' - date and time both

2. ' SD_DATETIME_DIFFERENCE ' - date and time both

3. 'HR_HK_DIFF_BT_2_DATES'

If hope this helps u out.

regards

note: Reward ig useful

[Former Member]

Hi Purru ,

U can have another approach to date difference. U can first convert the froamt then take the difference as follows

1. To convert Date Format using ABAP

data lv_date1 type sy-datum.

data lv_date2(12).

lv_date1 = '20070123'.

concatenate lv_date16(2) lv_date14(2) lv_date1+0(4) into lv_date2

separated by '.' .

is what you require to do;

now lv_date2 = 23.01.2007.

Also look for conversion routine "CONVERSION_EXIT_PDATE_OUTPUT"

EG: call function CONVERSION_EXIT_PDATE_OUTPUT

exporting input = lv_date1

importing output = lv_date2.

Also we can use function module ‘CONVERT_DATE_TO_EXTERNAL’ .

I hope this helps u out.

Regards.

note: Reward if useful

[Former Member]

if you want only the days between 2 dates then just subtract them

data : date1 like sy-datum value '20070206',
         date2 like sy-datum value '20060206',
         diff type i.

diff =  date1 - date2.

write : / diff.

[jayanthi_jayaraman]

Hi,

Try this code.

data days type i.

data : d1 type sy-datum,

d2 type sy-datum.

if suppose c1 is having '01.01.2006' and c2 is having '01.01.2005,

concatenate c16(4) c10(2) c1+3(2) into d1.

concatenate c26(4) c20(2) c2+3(2) into d2.

Now d1 = '20060101'.

d2 = '20050101'.

days = d1 - d2.

write days.

[Former Member]

Hi purshothaman,

1. days = 01.01.2006 - 01.01.2005

U already have the answer.

2. days = date1 - date2

will give the DIFFERENCE in days.

where days = i type variable

date1,date2 = sy-datum type variable

regards,

amit m.

[Former Member]

<b>DAYS_BETWEEN_TWO_DATES </b>

MONTHS_BETWEEN_TWO_DATES Integer number

CALL FUNCTION 'DAYS_BETWEEN_TWO_DATES'

EXPORTING

I_DATUM_BIS = x_faede-zfbdt

I_DATUM_VON = p_fdat

I_KZ_EXCL_VON = '0'

I_KZ_INCL_BIS = '0'

I_KZ_ULT_BIS = ' '

I_KZ_ULT_VON = ' '

I_STGMETH = '0'

I_SZBMETH = '1'

IMPORTING

E_TAGE = dias_v.

IF SY-SUBRC <> 0.

ENDIF.

donde:

x_faede-zfbdt -> 20050915

p_fdat -> 20050811

dias_v = 4

Message was edited by:

Judith Jessie Selvi