counting string length

[Former Member]

i want the count of the number of integers used in the string '1,2,10,22,3,5' leaving commas.

plz help.

[Former Member]

Hi

data:p_string.  "Your string

data :w_num(10) value '0123456789',
        count type i.

w_len = strlen(p_string)


do w_len times.



if p_string+count(count + 1) CA sy-abcde.      "if character add character to output

chara = charct + 1.

elseif p_string+count(count + 1) CA w_num.          "if chara cter is number adding to number

nunber = number + 1.
endif.

count = count + 1.
enddo.


write : charat.

write : number.

Regards,

Prabhudas

Edited by: Prabhu Das on Apr 17, 2009 4:58 PM

Edited by: Prabhu Das on Apr 17, 2009 4:59 PM

[Former Member]

Hi,

If the string has only integers and commas you can use:

FIND ALL OCCURRENCES OF ',' IN string MATCH COUNT mcnt.

The number of integers is mcnt + 1.

Regards.

Sandra Marques

[Former Member]

Hi,

p_string "input string.

data : w_num(10) type '0123456789'.

data : begin of itab occurs 0,
            num type char10.
         end of itab.

split p_string at ',' into itab.

loop at itab.
if itab-num CA w_num.
count = count + 1.
endif.
endloop.

[Former Member]

if its only commas and integers then you can do this way.

replace all occurence of ',' in p_string with space.
condense p_string.
len = strlen( p_string ).

Regards,

Lalit Mohan Gupta.

[Former Member]

hi sonu,

chk this code snippet.

REPORT  znitesh1.
DATA: a TYPE string VALUE '1,2,3,,4,5,6'.
DATA: b TYPE i VALUE 0.
REPLACE ALL OCCURRENCES OF ',' IN a WITH ' '.
b = STRLEN( a ).
WRITE b.

thanks

[Former Member]

if it is more than , and integers then you can do this way.

data: wa_num(10) value '0123456789',
count type i,
len type i.
len = strlen( p_string ).
do len times.
if p_string+0(1) ca wa_num.
count = count + 1.
endif.
shift p_string circular.
enddo.

Regards,

Lalit Mohan Gupta.