'ARCHIVE_READ_OBJECT'

[Former Member]

HI,

    In my program to retrive archived data, i am using ARCHIVE_READ_OBJECT FM.and into this i am passing key and offset,and i am getting the l_handle.here  upto my knowledge i should get L_handle as 1.but i am getting it as 765 .is this means any error in reading archiving data?.and i am writing another two form to retrive vbak and vbrk archived data and i am declaring parameters for all objects separately.

l_handle like sy-tabix.

CALL FUNCTION 'ARCHIVE_READ_OBJECT'

      EXPORTING

        object         = 'RV_LIKP'

        archivkey      = g_s_as_key-archivekey

        offset         = g_s_as_key-archiveofs

      IMPORTING

        archive_handle = l_handle

      EXCEPTIONS

        OTHERS         = 1.

[vigneshyeram]

This message was moderated.

[Former Member]

Hi Krishna,

Please check this example program.

SBOOKS

Hope its helpful for u.

Regards,

Santanu Mohapatra.

[thorsten_hopf]

Hi Krishna,

habe you tried retrieving the next record through ARCHIVE_GET_NEXT_RECORD using your l_handle as written in the documentation of the FM?

Best regards,

Thorsten

[vigneshyeram]

Hi Krishna,

Please try with this.

call function 'ARCHIVE_OPEN_FOR_READ'

       exporting

         archive_document  =  wa_arch_files-document

         archive_name      =  wa_arch_files-archiv_key

         object            =  lv_acc_doc_type "'FI_DOCUMNT'

       importing

         archive_handle    =  archive_handle.

call function 'ARCHIVE_GET_NEXT_OBJECT'

         exporting

           archive_handle  =  archive_handle

         importing

           object_id       =  obj_id

           object_offset   =  obj_offset

           archive_name    =  arc_name

         exceptions

           end_of_file     =  01.

Thanks & Regards,

Vignesh Yeram

[Former Member]

Yes,i tried retrieving the next record through ARCHIVE_GET_NEXT_RECORD using your l_handle and i am getting some data ,but my doubt is if l_handle=765 it starts retriving data from middle(765th rec)then wat abt 1-765 records?