Append statement

[Former Member]

Hi all,

In my program I am Writing an loop statement for table ITAB1 and in that loop i am writing

two(2) Read statements for ITAB2 and ITAB3.

Now i Need to append all the data in the tables ITAB1,ITAB2,ITAB3 to ITAB.

How can i write this Append Statement

Can i Append all the data in the three tables at a time or do i need to append one by one

Thanks

Ajay

[Former Member]

Hi,

If the type of the Internal table ITAB1,ITAB2,ITAB3 to ITAB are same then you can directly appen those to final internal table.

The statement is

APPEND ITAB1 to ITAB.

HERE ITAB1 is the workarea of the ITAB1 intearnal table.

same for rest of the internal tables.

Check this link for details-

http://help.sap.com/saphelp_nw04/helpdata/en/fc/eb36c8358411d1829f0000e829fbfe/content.htm

Regards,

Sujit

[Former Member]

Hi,

Loop at itab1

itab-filed = itab1-field

Read itab2.

if sy-subrac = 0.

itab-field = itab2-field.

endif.

Read itab3.

if sy-subrc = 0.

itab-field = itab3-field.

endif.

APPEND itab.

endloop.

thanks,

[Former Member]

Hi,

Please find my previous post for a similar requirement, it must help you..

With best wishes,

Rama.

[Former Member]

Hi Ajay,

Try using this :

Appending Several Lines

You can append internal tables to index tables using the following statement:

APPEND LINES OF <itab1> TO <itab2>.

This statement appends the whole of ITAB1 to ITAB2. ITAB1 can be any type of table, but its line type must be convertible into the line type of ITAB2.

When you append an index table to another index table, you can specify the lines to be appended as follows:

APPEND LINES OF <itab1> [FROM <n1>] [TO <n 2>] TO <itab2>.

<n 1 > and <n 2 > specify the indexes of the first and last lines of ITAB1 that you want to append to ITAB2.

This method of appending lines of one table to another is about 3 to 4 times faster than appending them line by line in a loop. After the APPEND statement, the system field SY-TABIX contains the index of the last line appended. When you append several lines to a sorted table, you must respect the unique key (if defined), and not violate the sort order. Otherwise, a runtime error will occur.

Regards,

Swapna.

[Former Member]

hi

yes u can

let the work area for this tables are

wa_itab1

wa_itab2

wa_itab3

now

loop at itab1 into wa_itab1.

ur frist read statement and u get thai record in wa_itab2.

then

ur second read statement and u get thai record in wa_itab3.

now

append wa_itab1 to itab.

append wa_itab2 to itab.

append wa_itab3 to itab.

endloop.

[Former Member]

Hello,

Here is one way.Assuming that ITAB1, ITAB2,ITAB3 and ITAB has similar Structures.

LOOP AT ITAB1.

MOVE-CORRESPONDING ITAB1 to ITAB.

READ TABLE ITAB2 with key F1 = ITAB1-F1 Bin Srch.

IF SY-SUBRC EQ 0.

MOVE-CORRESPONDING ITAB2 to ITAB.

ENDIF.

READ TABLE ITAB3 with key F1 = ITAB1-F1 Bin Srch.

IF SY-SUBRC EQ 0.

MOVE-CORRESPONDING ITAB3 to ITAB.

ENDIF.

APPEND ITAB.

ENDLOOP.

Hope it helps.

Thanks and Regards,

Venkat Phani Prasad Konduri

[GauthamV]

hi,

check this sample code.

Form final_table.

loop at it_bsis.

CLEAR IT_bkpf.

READ TABLE IT_bkpf WITH KEY bukrs = IT_bsis-bukrs

belnr = it_bsis-belnr

gjahr = it_bsis-gjahr.

IF SY-SUBRC = 0.

it_final-xblnr = it_bkpf-xblnr.

it_final-bukrs = it_bkpf-bukrs.

it_final-monat = it_bkpf-monat.

it_final-gjahr = it_bkpf-gjahr.

ENDIF.

CLEAR IT_bseg.

READ TABLE IT_bseg WITH KEY bukrs = IT_bkpf-bukrs

belnr = it_bkpf-belnr

gjahr = it_bkpf-gjahr

hkont = it_bsis-hkont

buzei = it_bsis-buzei.

IF SY-SUBRC = 0.

IT_FINAL-belnr = IT_bseg-belnr.

it_final-prctr = it_bseg-prctr.

IT_FINAL-gsber = IT_bseg-gsber.

it_final-bschl = it_bseg-bschl.

it_final-maber = it_bseg-maber.

ENDIF.

CLEAR IT_KNA1.

READ TABLE IT_KNA1 WITH KEY KUNNR = IT_acct-KndnR.

IF SY-SUBRC = 0.

IT_FINAL-KUNNR = IT_KNA1-KUNNR.

IT_FINAL-name1 = IT_KNA1-name1.

IT_FINAL-stras = IT_KNA1-stras.

IT_FINAL-ort01 = IT_KNA1-ort01.

ENDIF.

APPEND IT_FINAL.

CLEAR IT_FINAL.

endloop.

endform.

[Former Member]

Loop at itab1.

move-corresponding itab1 to itab.

read itab2.

move-corresponding itab2 to itab.

read itab3.

move-corresponding itab3 to itab.

append itab.

endloop.

Regards

Sathar

[Former Member]

Hi,

itab = itab1.

append itab.

itab = itab2.

append itab.

itab = itab3.

append itab.

i hope this will help you.

Regards,

Harish

[Former Member]

Hi Ajay,

Do it like this:

Loop at ITAB1 into WA1.

  Read table ITAB2 into WA2 with key field eq WA1-field.
  Read table ITAB3 into WA3 with key field eq WA1-field.

WA-field1 = WA1-field.
WA-field2 = WA2-field.
WA-field3 = WA3-field.

Append WA to ITAB.

Endloop.

With luck,

Pritam.