Adding a file to the application server

[Former Member]

Hi Friends,

I need to send few files into the same file on the application server. I have used OPEN DATASET...FOR APPENDING. But the file is adding the data to the already existing data instead of overwriting the already existing file. I need help to overcome this.

Thanks,

Raj

[Former Member]

Hi Raj,

Use syntax,

OPEN DATASET FNAME FOR OUTPUT MESSAGE MESS.

do not use for appending...

Regards,

Azaz.

[Former Member]

I tried with FOR OUTPUT but I cannot append by using FOR OUTPUT.

Thanks,

Raj

[Former Member]

Hi,

For not appending the file already present in the application server check the code present in the link,

http://help.sap.com/saphelp_47x200/helpdata/en/fc/eb3cc0358411d1829f0000e829fbfe/content.htm

For appending the data in the file,

http://help.sap.com/saphelp_47x200/helpdata/en/fc/eb3ccd358411d1829f0000e829fbfe/content.htm

Regards,

Azaz Ali.

[Former Member]

Hi Raj,

Try this if you want in binary mode,

OPEN DATASET FNAME FOR OUTPUT In binary mode .

Try this if you want in text mode,

OPEN DATASET FNAME FOR OUTPUT In text mode encoding default .

Please dont forget to reward all helpful answers.

Regards,

Azaz Ali.

[Former Member]

Hi,

Try removing the FOR APPENDING addition in the OPEN DATASET..

Thanks,

Naren

[Former Member]

Dear Raj

To keep it simple, take it this way:

p_file is the filename.

1. APPENDING MODE:

open dataset p_file <b>for APPENDING</b> in text mode encoding default.

Here, if p_file already exists it is opened to append the exisiting data in the file. If the file does not exist it is open a new file.

2. OUTPUT MODE:

open dataset p_file <b>for OUTPUT</b> in text mode encoding default.

Here everytime the file is opened as a new one.

Hope the above info helps you.

Kind Regards

Eswar