ABAP

[Former Member]

Hi all,

How will i get the last 6 letters from a variable that is of type character? And in that 6 letters i should not take preceding zero's if any.

TIA,

sinthu

[Former Member]

hi

use <b>offset</b>

data : str(16) value '111003456',

temp(10) type c,

c ,

a type i value 0,

count type i,

j type i value '0'.

count = strlen( str ).

a = strlen( str ).

count = count + 1.

do count times.

c = str+a(1).

if c ne '0'.

if j = 7.

exit.

else.

concatenate c temp into temp.

j = j + 1.

endif.

endif.

a = a - 1.

enddo.

write 😕 temp.

[Former Member]

hi Sinthu,

Use <b>offset</b>

i.e,

data var1(10) type c value 'sinthunair'.

var1 = var1 + 3(6) " this statement will fetch the last 6 characters to var1.

write var1 no-zero.

Regards,

Santosh

[Former Member]

hii

len = strlen(string) .

" this will

"calculate the length

" of your string

strlen = strlen - 6 . " since only last 6 letters are

" needed

<b>string_new = string + strlen(6) .</b> " this will

" capture last 6 letters

<b>CONDENSE string_new NO-ZERO NO GAPS .</b>

WRITE:/ string_new .

use offset with no zero and no gaps.

syntax:

<b><f>[+<o>][(<l>)]</b>

The operation of the statement is performed for the part of the field <f> that begins at position <o>+1 and has a length of <l>.

If the length <l> is not specified, the field is processed for all positions between <o> and the end of the field.

String = string1+3(4).

Assuming that string1 = ‘abcdefgjk’.

Here string will contain ‘defg’.

Regards

Naresh

[Former Member]

Hi,

w_length = strlen(w_field)

w_length = w_length - 6

w_newfield = w_field+w_length(6).

condense w_newfield.

Regards,

Ravi

[Former Member]

Hi Sinthu,

You can use Offset, and in case you do not want zeroes.

also use condense.

If this is useful, award points pls..

Regards,

Bharadwaj

[rahulkavuri]

data: char(10).

data: char2(6).

char2 = char+3(6).

This will work , please award points if found helpful

[Former Member]

Hi,

check this...

REPORT ZTEST_LAST_SIX_WITHOUTZERO                                .

data: char(12),
      six(6),
      len type i,
      len6 type i.

char = '123450000123'.

len = strlen( char ).

len6 = len - 6.

write char+len6(6) to six no-zero.

write six.

regards

vijay

[Former Member]

Hi

Check this code it will work for u

CONSTANTS: lc_6 TYPE i VALUE '6'.

DATA : lv_strlen TYPE i,

xv_offer_num type char20,

yv_offer_6ch type char6.

CLEAR : lv_strlen.

• Calculate String Lenght

lv_strlen = STRLEN( xv_offer_num ).

• Take last 6 charectors

IF lv_strlen >= lc_6.

lv_strlen = lv_strlen - lc_6.

yv_offer_6ch = xv_offer_num+lv_strlen(lc_3).

ELSE.

yv_offer_6ch = xv_offer_num.

ENDIF.

Reward Points if solved.

to remove leading zero

conversion_exit_alpha_output........fm and pass yv_offer_6ch has input and output parameter

Reagards.

[Former Member]

Hi Sinthu,

The below code may help you in solving your problem.

data:

cc(10) type c value '0000000089',

len type i.

len = strlen( cc ). "To get length of character string

len = len - 6. "Offset for last six characters

write cc+len(6) no-zero to cc. "no-zeros in the result

condense cc. "Codensing the result

write:/ cc.

Thanks,

Vinay