ABAP String processing using normal methods

[Former Member]

I have a string like this:

A:12345;B:34324;C:443232;

Question 1)

How do I extract B:34324 from the above string?

Note: I can only use methods provided in ABAP programming (BC-ABA) such as split, CO, CA,etc

Question 2)

How do I know how many ';' characters the string contains?

Question 3)

How do I know the position of "B:" in the string?

Please help.

Thanks and best regards,

[Former Member]

You need to read this:

http://www.sapdb.info/abap-programs-string-operations/

[Former Member]

Check this sample code

data : text(100) value 'A:12345;B:34324;C:443232;'.
data : itab(50) occurs 0 with header line.
split text at ';' into table itab.
loop at itab.
if itab ca 'B'.
 write : / itab.
endif.
endloop.

Regards

Shiba Prasad Dutta

[Former Member]

Hi,

Please find code below for the Question 1:

DATA: v_string TYPE string,

v_one TYPE string,

v_two TYPE string,

v_three TYPE string.

CONSTANTS: c_colon TYPE char1 VALUE ';'.

v_string = 'A:12345;B:34324;C:443232'.

SPLIT v_string AT c_colon INTO v_one v_two v_three.

WRITE:/ v_two.

The variable V_TWO contains 'B:34324'.

Hope this solves your problem.

Regards,

Lavanya

[Former Member]

Hi,

The same code can be used for the question 2:

DATA : text(100) VALUE 'A:12345;B:34324;C:443232;',

v_count TYPE sytabix.

DATA : itab(50) OCCURS 0 WITH HEADER LINE.

SPLIT text AT ':' INTO TABLE itab.

CLEAR v_count.

LOOP AT itab.

IF itab CA ';'.

v_count = v_count + 1.

ENDIF.

ENDLOOP.

WRITE:/ v_count.

Regards,

Lavanya.

[Former Member]

I got this error message when compile:

The addition of OCCURS is no longer supported in the OO context. Use "Table of ... Intial size" instaead.

So what is the actual syntax like? Help me.

[Former Member]

Hi,

Please find the correct syntax:

DATA: text(100) VALUE 'A:12345;B:34324;C:443232;',
      v_count TYPE sytabix.

TYPES: BEGIN OF ty_itab,
         text(50),
       END OF ty_itab.

DATA: itab TYPE TABLE OF ty_itab,
      wa_itab TYPE ty_itab.

SPLIT text AT ':' INTO TABLE itab.

CLEAR v_count.
LOOP AT itab INTO wa_itab.
  IF wa_itab-text CA ';'.
    v_count = v_count + 1.
  ENDIF.
ENDLOOP.

WRITE:/ v_count.

Regards,

Lavanya.

Edited by: Lavanya Gourisetty on Dec 22, 2008 12:41 PM

[Former Member]

Hi,

Question 3)
How do I know the position of "B:" in the string?

Check this

DATA a TYPE string value  'A:12345;B:34324;C:443232'.
DATA c TYPE i.
DATA d TYPE c.
DATA e TYPE i VALUE 0.
DATA f TYPE i VALUE 0.
c = STRLEN( a ).

DO c TIMES.
  d = a+e(1).
  e = e + 1.
  f = f + 1.
  IF d EQ 'B'.
    EXIT.
  ENDIF.
ENDDO.
WRITE f.

Thanks

[Former Member]

Hi,

Try this

DATA : char03 TYPE string VALUE 'A1234;B5678;C9012;',

char04 TYPE string,

len1 type sy-fdpos.

data char_tab type table of string.

split char03 at ';' into table char_tab.

search char03 for 'B'.

len1 = sy-fdpos. " Position of B

Regards,