on 06-23-2008 1:59 PM
Hi all,
I need to open an external URL (for instance,www.google.com) from my WDA application by 'linktoaction' or 'button' event and this should be happen in the same parent window and not as a external window.
Please suggest me steps with example codes to perform this.
Regards,
Dinesh
Why use a linktoaction? Just use a linkToURL.
[http://help.sap.com/saphelp_nw70/helpdata/EN/49/e8884118aa1709e10000000a155106/frameset.htm|http://help.sap.com/saphelp_nw70/helpdata/EN/49/e8884118aa1709e10000000a155106/frameset.htm]
You can use the target property to control how the link opens.
If you must use a button or linkToAction, the you will have to use an Exit Plug:
[http://help.sap.com/saphelp_nw70/helpdata/EN/45/1bc575ba064574e10000000a114a6b/frameset.htm|http://help.sap.com/saphelp_nw70/helpdata/EN/45/1bc575ba064574e10000000a114a6b/frameset.htm]
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Hi,
Thanks for your reply.
In have added these lines..
data: L_REF_MAIN_WINDOW type ref to IG_zws_wda .
L_REF_MAIN_WINDOW = WD_THIS->GET_Zws_wda_CTR( ).
L_REF_MAIN_WINDOW->FIRE_OUT_PLG(
URL = 'http://www.google.com' " String
).
It throws an error that
" Method GET_Zws_wda_CTR is unknown or PROTECTED or PRIVATE"
can u pls suggest any solution...
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