XSLT problem with Carriage return in Web Dynpro

[former_member336373]

My problem is:

In java application, I can tranform the xml file into another format with a certain stylesheet(XSL file) properly. But when I use the same code and the same XSL file to do the transformation in Web Dynpro, it outputs the wrong result, in which all the <b>Carriage Return disappears</b>.

Here is the example:

-Input file (source.xml)-

<?xml version="1.0"?>

<?xml-stylesheet type='text/xsl'>

<List>

<Name age="20">Sandy</Name>

<Name age="23">Sue</Name>

<Name age="18">Billy</Name>

</List>

-XSL file-

<?xml version="1.0"?>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="text"/>

<xsl:variable name="newline">

<xsl:text>&#xA;</xsl:text>

</xsl:variable>

<xsl:variable name="space">

<xsl:text> </xsl:text>

</xsl:variable>

<xsl:template match="/">

<xsl:for-each select="List/Name">

<xsl:value-of select="."/>

<xsl:value-of select="$space"/>

<xsl:value-of select="@age"/>

<xsl:value-of select="$newline"/>

</xsl:for-each>

</xsl:template>

</xsl:stylesheet>

In java app:

-Output file (DesJava.txt)->(Right result)

Sandy 20

Sue 23

Billy 18

In Web Dynpro:

-Output file (DesWebDynpro.txt)->(Wrong result)

Sandy 20Sue 23Billy 18

All above shows, in Web Dynpro the Carriage Return symbol is dismissed.

Anybody know the reason and the solution to solve this problem?

Thanks

[former_member182372 · Accepted solution]

Hello Irene,

Are you using Dynpro to create file containing results of transformation or you are using some UI elements to display such results?

BTW, why are you using

	<xsl:variable name="newline">
		<xsl:text>&#xA;</xsl:text>
	</xsl:variable>

Try this one

<xsl:variable name="newline" select="'&#13;&#10;'"/>

Best regards, Maksim Rashchynski.

[former_member336373 · Accepted solution]

Hi,Maksim

I just use Dynpro to create transformation result.

Finally I solved the problem under your tips.

Here, the format

<xsl:variable name="newline"> <xsl:text>&#xA;</xsl:text>

</xsl:variable>

is OK for XSL. The reason for the problem is the wrong use of '&#Xa;'.

I tried to use '&#13;&#10;' to replace the '&#Xa;', then I got the expected result. Great!

Below is the right lines now I use:

<xsl:variable name="newline"> <xsl:text>&#13;&#10;</xsl:text>

</xsl:variable>

Although I have solved the problem, I wonder why I can't use &#xa; to present the Carriage Return. In fact, '&#xa;' works well in JAVA.

[former_member182372 · Accepted solution]

Hello Irene,

If the problem is solved, please assign points "Solved problem" and close thread.

Best regards, Maksim Rashchynski.

[former_member318735 · Accepted solution]

Hi,

How did you parse xml document via dynpro application. Could you please tell me more about steps.