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Standard function to find alphabet in string?

Former Member
0 Kudos

Is there a standard function to find alphabet in string?

For example, a variable define as char (10),

I need a function to find out if this variable contains alphabet.

Any standard function there?

19 REPLIES 19

JozsefSzikszai
Active Contributor
0 Kudos

hi,

you don't need a function:

IF char CA sy-abcde.
==> it contains at least one letter
ELSE.
==> it does not contain any letter
ENDIF.

hope this helps

ec

Former Member
0 Kudos

use-

DATA str(10).

if str CA sy-abcde.

"--> contains alphabet

else.

"--> does not contain alphabet

endif.

Regards,

Aparna Gaikwad

0 Kudos

Thanks, I will try.

0 Kudos

Thanks

Former Member
0 Kudos

hiii

try using FM

DX_SEARCH_STRING

you can use logic like

len = strlen( wa_str ).
do.
   if ofset = len.
    exit.
  endif.
 if wa_string+ofset(1) co sy-abcde  .
      concatenate wa_string+ofset(1) into wa_final.

regards

twinkal

Former Member
0 Kudos

Hi Lin,

Try the following:

parameters: p_char type c.

search sy-abcde for p_char.

if sy-subrc eq 0.
write: 'Found'.
else.
write: 'Not Found'.
endif.

Regards,

Chandra Sekhar

Former Member
0 Kudos

I tried use sy-abcde,but still can not get right result.

I think it only recognize Capital letter.

Edited by: lin tao on Sep 1, 2008 11:33 AM

0 Kudos

just copy your code here, and explain what happens and what do you expect to happen...

0 Kudos

Try this

take a variable and make its value as shown

v_abcde type char60 value 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghi...xyz'.

Now compare your variable suppose v_str as

If v_str CA v_abcde.

..

else.

..

Endif.

This will help!

Regards,

Prashant

0 Kudos
I think it only recognize Capital letter.

post your code here.

Amit.

0 Kudos

My code:

data: p_char(10) type c value'3001d0001'.

search sy-abcde for p_char.

if sy-subrc eq 0.

write: 'Found'.

else.

write: 'Not Found'.

endif.

if p_char CA sy-abcde.

write: 'Found'.

else.

write: 'Not Found'.

endif.

-


the output is Not found, Not found.

If I change value'3001D0001'

the output is Not found, found.

0 Kudos

hii

use following code

data: wa_str(100) type c.
data: wa_str1 type string.
data: wa_str2 type string.
data: wa_str3 type string.


data: len type i.
data: ofset type i.

wa_str = 'ABCD7788HJK.
len = strlen( wa_str ).
do.
  if ofset = len.
    exit.
  endif.

 if wa_str+ofset(1) co sy-abcde  .
      concatenate wa_str2 wa_str+ofset(1) into wa_str2.
else.
    concatenate wa_str3 wa_str+ofset(1) into wa_str3.
  endif.

  ofset = ofset + 1.

enddo.
write:/ wa_str.
write:/ 'alphabate ::',  wa_str2.

regards

twinkal

0 Kudos

I expect the program to recongnize both upper case and lower case letter. as long as the string contains any alph, it should ouput found.

0 Kudos
data: p_char(10) type c value'3001d0001'.
TRANSLATE p_char TO UPPER CASE.
if p_char CA sy-abcde.


if sy-subrc eq 0.
write: 'Found'.
else.
write: 'Not Found'.
endif.
endif.

in both case of D and d i got the output found.

Amit.

Former Member
0 Kudos

Hi lin,

You can use this code to check a variable.

IF VAR1 CA SY-ABCDE.

  • DO YOUR CALCULATION.

ENDIF.

<removed_by_moderator>

Edited by: Julius Bussche on Sep 1, 2008 10:06 AM

Former Member
0 Kudos

Hi, maby it's not the full alfabeth but just some of it.

Then the CS 'ABCDE' (contain string) can be usefull.

/Tom

Former Member
0 Kudos

hiii

use following code

data: wa_str(100) type c.
data: wa_str1 type string.
data: wa_str2 type string.
data: wa_str3 type string.


data: len type i.
data: ofset type i.

wa_str = 'ABCD435hjK'.
len = strlen( wa_str ).

TRANSLATE wa_str TO UPPER CASE.

do.
  if ofset = len.
    exit.
  endif.

 if wa_str+ofset(1) co sy-abcde  .
      concatenate wa_str2 wa_str+ofset(1) into wa_str2.
else.
    concatenate wa_str3 wa_str+ofset(1) into wa_str3.
  endif.

  ofset = ofset + 1.

enddo.


write:/ wa_str.
write:/ 'alphabatic char', 20 wa_str2.

here TRANSLATE wa_str TO UPPER CASE.

statement have added .i hope this will solve your problem.

regards

twinkal

former_member705122
Active Contributor
0 Kudos

Hi,

Please ignore this.

Edited by: Syed Abdul Adil on Sep 1, 2008 12:31 PM

Former Member
0 Kudos

Thank you for you all.

The problem is solved now.