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Offset length error in a Unicode system

Former Member
0 Kudos
857

Hi All,

I have a offset error as follows:

The offset declaration "52" exceeds the length of the character-type start (=15) of the structure. This is not allowed in Unicode programs.

The syntax in 4.6c system is: SHIFT int_usr02+52 LEFT BY 4 PLACES.

But in ECC am getting a syntax error as described above.

int_usr02 is defined as: data: int_usr02 LIKE usr02 OCCURS 0 WITH HEADER LINE.

And usr02 is transp.table.

Please guide me.

Your help will be much appreciated

Thanks in Advance,

Indu.

1 ACCEPTED SOLUTION

Former Member
0 Kudos
141

add the below code

FIELD-SYMBOLS : <FS_USR01>.

DATA : L_LEN TYPE I,

L_LIN TYPE I.

ASSIGN INT_USR02 TO <FS_USR01> CASTING TYPE C.

DESCRIBE FIELD <FS_USR01> LENGTH L_LIN IN CHARACTER MODE.

L_LEN = L_LIN - 52.

SHIFT <FS_USR01>+52(L_LEN) LEFT BY 4 PLACES.

4 REPLIES 4

Former Member
0 Kudos
141

Hi Indumati,

try this

it will definitely work

SHIFT int_usr02+52 LEFT BY 4 PLACES

sol:

SHIFT int_usr02-FieldName+52(specify length here) LEFT BY 4 PLACES

syntax:

SHIFT Field+offset(len) LEFT BY 4 PLACES

Regarda,

Chinna

Former Member
0 Kudos
141

Hello,

As said by you that USR02 is a Transparent table (I too know that ), you need to specify the field name while you are using the offset.

Hope it helps.

Thanks,

Jayant

Former Member
0 Kudos
142

add the below code

FIELD-SYMBOLS : <FS_USR01>.

DATA : L_LEN TYPE I,

L_LIN TYPE I.

ASSIGN INT_USR02 TO <FS_USR01> CASTING TYPE C.

DESCRIBE FIELD <FS_USR01> LENGTH L_LIN IN CHARACTER MODE.

L_LEN = L_LIN - 52.

SHIFT <FS_USR01>+52(L_LEN) LEFT BY 4 PLACES.

0 Kudos
141

Hi Sreekanth,

Thanks a lot for the immediate and helpful answer.The code solved my problem.Thanks again.

Regards,

Indu