Brain Twister's!!!

[Former Member]

Hi All,

Here is the question,

1) I am having one object of 40 kgs which need to be splitted into 4 equal parts.

of which taking their combinations we can measure from 1kg to 40 kgs objects.

For example:

1)I want to weight 12 sugar...

i can put 2 combinations(10 + 2) on one side and other side 12 sugar

2) another is if i want to weight 15 kgs where i cant have 15 kgs combination ...

then i will put

20 kgs weight on one side and 15 sugar + 5 kgs on other side...

Hint is No need to split it in decimals....

Question:what are those 4 combinations?

Regards

sas

[Former Member]

40 kgs which need to be splitted into 4 equal parts.

Obviously the only solution for this:

w=x=y=z=10

But no way to fulfill the second requirement...

And by the way, I remember having seen a solution for what you probably intended.

But not going to spoil it for others.

regards

[Former Member]

Humm....Good that atleast you tried.....

and that is like 10% answer

Lets see what others say..whats up any one there

regards

sas

[Former Member]

Hi,

The answer is 1, 3, 9, 27 !!!!

DVRk

[matt]

So, if w, x, y and z are the weights, then we need to find integer w, x, y, z such that there exists, for all n between 1 and 40, a, b, c, d, e, f, g, h where a.w + b.x + c.y + d.z - e.w - f.x - g.y -h.z = n, and a to h have value either 1 or zero and a.d = b.e = c.g = d.h = 0.

[Former Member]

>

> So, if w, x, y and z are the weights, then we need to find integer w, x, y, z such that there exists, for all n between 1 and 40, a, b, c, d, e, f, g, h where a.w + b.x + c.y + d.z - e.w - f.x - g.y -h.z = n, and a to h have value either 1 or zero and a.d = b.e = c.g = d.h = 0.

Ha Ha

Hy upto w , x , y , z are weights is correct!!

But remaning all are crapy

easy :

w+ x + y + z = 40.

Oh...No one not even able to get edge atleast :(..Hope Now US guys will have a try

Regards

sas

Edited by: saslove sap on Apr 6, 2009 4:10 PM

[matt]

>

> >

> > So, if w, x, y and z are the weights, then we need to find integer w, x, y, z such that there exists, for all n between 1 and 40, a, b, c, d, e, f, g, h where a.w + b.x + c.y + d.z - e.w - f.x - g.y -h.z = n, and a to h have value either 1 or zero and a.d = b.e = c.g = d.h = 0.

>

> Ha Ha

> Hy upto w , x , y , z are weights is correct!!

> But remaning all are crapy

> easy :

> w+ x + y + z = 40.

>

> Oh...No one not even able to get edge atleast :(..Hope Now US guys will have a try

> Regards

> sas

>

> Edited by: saslove sap on Apr 6, 2009 4:10 PM

I guess you didn't major in maths!

Put the item you wish to weigh on the right hand bowl of the scale. Then they'll be balanced by the weights as follows (L = weight on left side, R = weight on right side ).

_27-9-3-1 1-_-_-_-L 2-_-_-L-R 3-_-_-L- 4-_-_-L-L 5-_-L-R-R 6-_-L-R- 7-_-L-R-L 8-_-L-_-R 9-_-L-_- 10-_-L-_-L 11-_-L-L-R 12-_-L-L- 13-_-L-L-L 14-L-R-R-R 15-L-R-R- 16-L-R-R-L 17-L-R-_-R 18-L-R-_- 19-L-R-_-L 20-L-R-L-R 21-L-R-L- 22-L-R-L-L 23-L-_-R-R 24-L-_-R- 25-L-_-R-L 26-L-_-_-R 27-L-_-_- 28-L-_-_-L 29-L-_-L-R 30-L-_-L- 31-L-_-L-L 32-L-L-R-R 33-L-L-R- 34-L-L-R-L 35-L-L-_-R 36-L-L-_- 37-L-L-_-L 38-L-L-L-R 39-L-L-L- 40-L-L-L-L

matt

[Former Member]

Hy Matt You are The Mannnnnnnnnnnnnnnnnnn

So nice of you !! You have one a nice Harshey Chocolate Enjoy the day

Regards

sas

Maths ohh...Matt that is the only subject in my whole career i never lost 1 mark even !! My All time favourite

Edited by: saslove sap on Apr 7, 2009 10:23 AM

[Former Member]

>

> Hy Matt  You are The Mannnnnnnnnnnnnnnnnnn

Any Clue , Please! ?;-)

Cheers