on ‎2019 Dec 12 11:41 AM
I have an HTML mashup in C4C which contains links to other pages that accept a 'return URL' parameter. These pages use that parameter to provide a link to get back to the original page (i.e. the HTML mashup)
When I inspect the source of the HTML mashup frame the URL is:
https://mashup-de.sapbydesignmashups.com/mashups/html/render
However, if I provide this as the Return URL, it just stays on the 'Loading...' page and doesn't reload the mashup. Does anyone know of a way to trigger the mashup to load again via the URL?
Unfortunately I don't have control of the pages I'm linking to, so am not able to modify how they work (e.g. by using a browser 'back' function instead.. which does work!)
Thanks,
Simon
Request clarification before answering.
Hi,
Did you create a reverse navigation for your mashup in order to navigate back from custom URL to C4C UI? If not, I would highly encourage to check this blog:
https://blogs.sap.com/2019/05/14/c4c-mashups-how-to-return-data-from-a-mashup-to-c4c/
I know that in your case you are just returning back the URL and no data being transferred but in order to get the control back from external iframe to C4C, a dummy navigation has to take place.
I haven't tried this approach very recently but a couple of years back and it worked for me.
Thanks
Saurabh
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I'm using this blog https://blogs.sap.com/2020/01/27/adding-an-html-mashup-to-opportunity-to-display-detailed-status-and... However, the mashup doesn't work and I have also a rendering issue: https://mashup-de.sapbydesignmashups.com/mashups/html/render
Saurabh do you have any idea?
Thanks,
Daan
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