OUTPUT OF THIS CODE

[Former Member]

what will this code get melst_exchdr TYPE J_1IEXCHDR.

lst_exchdr-EXNUM = J_1IEXCHDR-EXNUM.

DATA: BEGIN OF j1ii300,

sergrp LIKE j_1isrgrps-j_1isergrp,

END OF j1ii300.

DATA: BEGIN OF idata,

excnum LIKE j_1iexchdr-exnum,

exyear LIKE bkpf-gjahr,

END OF idata.

CALL FUNCTION 'NUMBER_GET_NEXT'

EXPORTING

nr_range_nr = '01'

object = 'J_1IEXCLOC'

QUANTITY = '1'

SUBOBJECT = j1ii300-sergrp

TOYEAR = idata-exyear

• IGNORE_BUFFER = ' '

IMPORTING

NUMBER = idata-excnum

• QUANTITY =

• RETURNCODE =

EXCEPTIONS

INTERVAL_NOT_FOUND = 1

NUMBER_RANGE_NOT_INTERN = 2

OBJECT_NOT_FOUND = 3

QUANTITY_IS_0 = 4

QUANTITY_IS_NOT_1 = 5

INTERVAL_OVERFLOW = 6

BUFFER_OVERFLOW = 7

OTHERS = 8

.

IF sy-subrc <> 0.

• MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO

• WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.

ENDIF.

IF idata-excnum <> lst_exchdr-exnum.

will it get the next number range for the object

or the next invoice number in the table j_1iexchdr

[Former Member]

It will give the next number of the object.

Vinodh Balakrishnan