Get XML data

[Former Member]

Hi to all,

I want to read a XML document containing in a tree (Linked objects).

In my program I use the method CL_SCMG_CASE_API-GET_BACKEND_RECORD (view code).

This method returns a ref to CL_SCMG_REC_CASE_BE.

The structure G_CONTENT_XML_BUFFER of this class contains a table (BIN_CONTENT_TAB) with 14 lines type x(1022):

3C3F786D6C2076657273696F6E............

72696E67222064656661756C74............

I think this is the content of XML. How could I convert the lines to the XML data?

Could I do it in another way?

This is the code:

INCLUDE <cntn01>.

DATA:

bor_case TYPE swc_object,

container_tab TYPE STANDARD TABLE OF swcont.

DATA BEGIN OF swo_return.

INCLUDE STRUCTURE swotreturn.

DATA END OF swo_return.

DATA: l_ref_if_scmg_case_api TYPE REF TO if_scmg_case_api,

case_type TYPE scmgcase_type,

tty_namevalueasstring TYPE ty_namevalueasstring.

bor_case-header = 'OBJH'.

bor_case-type = 'SWO '.

CALL FUNCTION 'SWO_CREATE'

EXPORTING

objtype = 'SCASE'

objkey = 'DC0D01..........'

IMPORTING

object = bor_case-handle

return = swo_return.

IF swo_return-code NE 0.

bor_case-handle = 0.

ENDIF.

CALL METHOD cl_scmg_case_api=>read_case_type

EXPORTING

im_case_guid = 'DC0D01..........'

RECEIVING

re_case_type = case_type.

CALL METHOD cl_scmg_case_api=>if_scmg_case_api~create

EXPORTING

im_case_type = case_type

im_case_guid = 'DC0D01..........'

RECEIVING

re_case = l_ref_if_scmg_case_api

EXCEPTIONS

failed = 1

no_authority = 2

path_creation_failed = 3

others = 4

.

IF sy-subrc EQ 0.

ENDIF.

data: l_ref_IF_SRM_SP_RECORD type ref to IF_SRM_SP_RECORD.

CALL METHOD l_ref_if_scmg_case_api->get_backend_record

receiving

re_record_backend = l_ref_IF_SRM_SP_RECORD

EXCEPTIONS

failed = 1

others = 2

.

IF sy-subrc <> 0.

ENDIF.

[uwe_schieferstein]

Hello Anja

For displaying the XML you can use class<b> CL_XML_DOCUMENT</b>. Create an instance of this class and call methods:

PARSE_TABLE (convert XML stream -> DOM)     " followed by
DISPLAY

Using method GET_AS_TABLE (use table of type STRING) you should be able to retrieve the XML as string.

Regards

Uwe

[Former Member]

Hi Uwe.

Can you explain "convert XML stream -> DOM"?

Thanks.

[uwe_schieferstein]

Hello Anja

The stream is

3C3F786D6C2076657273696F6E............

72696E67222064656661756C74............

as you described. The method converts this byte stream into a <b>document object model</b> (DOM) representing the hierarchical XML structure.

For sample reports please refer to package <b>SIXML_TEST</b>.

Regards

Uwe