topic Re: initial of strings in Application Development and Automation Discussions

initial of strings

Former Member — Thu, 17 Jul 2008 08:54:54 GMT

variable = 'NEW YORK'.

now i want only NY into another variable.

That mean starting N and if there is a space between 2 words then i want starting of that 1.

Re: initial of strings

Former Member — Thu, 17 Jul 2008 08:57:33 GMT

split variable at '' into v_str1 v_str2 .

concatenate v_str10(1) v_str20(1) into v_new.

Re: initial of strings

Former Member — Thu, 17 Jul 2008 09:11:05 GMT

hi,

You can try that.

len = strlen(string).

do len times.
w_in = sy-index.
if string+w_in(1) = space.
w_ind = w_in.
add 1 to w_ind.
concatenate substr string+w_ind(1) into substr.
endif.
enddo.

SUBSTR will contain Initials.

Regards

Sumit Agarwal

Re: initial of strings

Former Member — Thu, 17 Jul 2008 09:55:43 GMT

Hi Dear


DATA  :  V_VERIABLE  TYPE STRING.
DATA  :  V_VER_NEW   TYPE STRING.

DATA  :  ITAB TYPE TABLE OF STRING.
DATA  :  WTAB TYPE STRING.

V_VERIABLE = 'New York TEST TEXT'.

SPLIT V_VERIABLE AT SPACE INTO : TABLE ITAB.

LOOP AT ITAB INTO WTAB.

CONCATENATE V_VER_NEW WTAB(1) INTO V_VER_NEW.
ENDLOOP.


WRITE:/ V_VER_NEW.

Rewards if useful.

Re: initial of strings

Former Member — Thu, 17 Jul 2008 12:13:06 GMT

ok that is working

what is there is no space i.e., if i get only 1 word

Case 1: 'New York'. requirement is get NY

Case 2: 'Florida' requirement is get FL

Can you please take look of it

Re: initial of strings

Former Member — Thu, 17 Jul 2008 12:14:01 GMT

ok that is working

what is there is no space i.e., if i get only 1 word

Case 1: 'New York'. requirement is get NY

Case 2: 'Florida' requirement is get FL

Can you please take look of it

Re: initial of strings

Former Member — Thu, 17 Jul 2008 12:14:21 GMT

ok that is working

what is there is no space i.e., if i get only 1 word

Case 1: 'New York'. requirement is get NY

Case 2: 'Florida' requirement is get FL

Can you please take look of it

Re: initial of strings

Former Member — Thu, 17 Jul 2008 12:16:00 GMT

hiiii

if your requirement is for getting short name from any word then only way is use OFFSET for every word..

like for florida use like w_short = 0(2).

regards

twinkal

Re: initial of strings

Former Member — Thu, 17 Jul 2008 12:17:43 GMT

wht if its Louisiana?? its LA for louisiana.

ur approach is wrong. u must search for something that is SAP-defined..

Re: initial of strings

JozsefSzikszai — Thu, 17 Jul 2008 12:18:17 GMT

can you check if table T005S (with country = US) does contain what you need?

Re: initial of strings

Subhankar — Thu, 17 Jul 2008 12:24:42 GMT

Please do it in this way

data: l_str1 TYPE string,

l_str2 TYPE string,

l_str3 TYPE string,

l_out TYPE char04.

l_str1 = 'ABC XYZ'.

SPLIT l_str1 at space INTO l_str2 l_str3.

if l_str3 is INITIAL.

l_out = l_str2(1).

else.

CONCATENATE l_str2(1) l_str3(1) INTO l_out.

endif.

WRITE : l_out.

Re: initial of strings

Former Member — Fri, 18 Jul 2008 02:42:39 GMT

Dear Syed

change my previous code as bellow.


DATA  :  V_VERIABLE  TYPE STRING.
DATA  :  V_VER_NEW   TYPE STRING.
DATA  :  V_DBCNT     TYPE SY-DBCNT.

DATA  :  ITAB TYPE TABLE OF STRING.
DATA  :  WTAB TYPE STRING.

V_VERIABLE = 'Florida'.

SPLIT V_VERIABLE AT SPACE INTO : TABLE ITAB.

DESCRIBE TABLE ITAB LINES V_DBCNT.
IF V_DBCNT > 1.
LOOP AT ITAB INTO WTAB.
CONCATENATE V_VER_NEW WTAB(1) INTO V_VER_NEW.
ENDLOOP.
ELSE.
V_VER_NEW = V_VERIABLE(2).
ENDIF.

WRITE:/ V_VER_NEW.

Rewards if helpful.