topic Re: replace in Application Development and Automation Discussions

replace

Former Member — Mon, 07 Jul 2008 07:09:12 GMT

Hi ,

How to replace last occurrence of a character in a string .

eg: aaaaxaaaxaaaxaaa

so i need last x should be replaced with y

output : aaaaxaaaxaaayaaa

Re: replace

Former Member — Mon, 07 Jul 2008 07:12:06 GMT

good

step 1- store the value in a string

step 2- get the lenght of the string

step 3- get the position of the last y from the string

step 4- use replace statement to replace the x with y

Thanks

mrutyun^

Re: replace

Former Member — Mon, 07 Jul 2008 07:18:20 GMT

Hi,

Try this coding using the Function Module.

DATA: v_string TYPE string.

v_string = 'HOPT & SCHULER GMBH & CO KG'.

CALL FUNCTION 'WRB_UTIL_STRING_REPLACE'

EXPORTING

pi_search_string = '&'

pi_replace_string = '''&'''

CHANGING

pc_string = v_string

EXCEPTIONS

search_string_too_long = 1

missing_search_string = 2

OTHERS = 3.

IF sy-subrc = 0.

WRITE: / v_string.

ENDIF.

Hope this helps you.

Rewars points of helpfull.

Thanks & Regards,

Y.R.Prem Kumar

Re: replace

JozsefSzikszai — Mon, 07 Jul 2008 07:19:43 GMT

bad

I am not sure if there is a direct way, but you can try the following:

1. Reverse the string with FM STRING_REVERSE, so the last x will be the first

2. Now you can use RAPLACE ... FIRST OCCURANCE ...

3. Reverse the string again with FM STRING_REVERSE

hope this helps

Re: replace

Former Member — Mon, 07 Jul 2008 07:20:49 GMT

Hi,

plz try this :

data: text type string.

text = 'aaaaxaaaxaaaxaaa'.

REPLACE SECTION OFFSET 12 OF text WITH 'yaaa'.
 write: text.

text = aaaaxaaaxaaayaaa.

hope this helps you.

plz reward if useful.

thanks,

dhanashri.

Re: replace

Former Member — Mon, 07 Jul 2008 08:01:42 GMT

try this code

data: len(2) type n,

count(2) type n,

count1(2) type n.

parameter str(40) type c.

start-of-selection.

len = strlen( str ).

clear count.

do len times.

if str+count(1) = 'X'.

COUNT1 = SY-INDEX.

ENDIF.

COUNT = COUNT + 1.

ENDDO.

count1 = count1 - 1.

IF COUNT1 = 0.

str+0(1) = 'y'.

ELSE.

str+count1(1) = 'y'.

ENDIF.

write:/ str.

Re: replace

dmitry_sharshatkin — Fri, 11 Mar 2016 09:44:14 GMT

I’mnot happy with all above, so I’m posting my variant:

data: str       type string value 'A,B,C,D,E,F,G,H,',
      ls_result type match_result.

find all occurrences of ',' in str results ls_result.
if sy-subrc = 0.
if ls_result-offset > 0 and
     ls_result-offset < strlen( str ).
    replace section offset ls_result-offset length 1 of str with '' in character mode.
    condense str no-gaps.
endif.
endif.

write: str.

Regards, Dima

Re: replace

Former Member — Fri, 11 Mar 2016 10:56:05 GMT

In your replace command use a regular expression to find the last occurrence of the character you wish to change.

This: "x(?:.(?!x))+$" (without the quotes) will find the last occurrence of x in a string.

Rich

Re: replace

dmitry_sharshatkin — Fri, 11 Mar 2016 12:00:58 GMT

Hi Rich,

Does not work with commas...

BR, Dima

Re: replace

Former Member — Fri, 11 Mar 2016 12:40:17 GMT

Did you modify the regex - I did say x. The OP did not specify another character.

Rich

Re: replace

Former Member — Fri, 11 Mar 2016 12:46:29 GMT

For commas:

,(?=[^,]*$)

Re: replace

dmitry_sharshatkin — Fri, 11 Mar 2016 13:08:00 GMT

Thanks! Works nice, will learn regex.

BR, Dima