topic Re: replace in Application Development and Automation Discussions

replace

Former Member — Mon, 30 Jun 2008 10:27:39 GMT

Hye Gurus,

i have a variable of type char40.

when i am using

replace all occurences of space in var with '_'.

it is throwing an exception.

Please suggest, my requirement is i have to replace spaces with underscore '_'.

Thanks in advance,

Imran.

Re: replace

JozsefSzikszai — Mon, 30 Jun 2008 10:30:40 GMT

hi,

you can do with TRANSLATE:

TRANSLATE string USING ' _'.

(pls note there is a space before the undescore)

hope this helps

Re: replace

former_member188827 — Mon, 30 Jun 2008 10:31:35 GMT

what is the exception text?

Re: replace

Former Member — Mon, 30 Jun 2008 10:33:29 GMT

Hi Imran,

Try these examples. :

Addition 1

... FIRST OCCURRENCE OF

Effect

In the string text, replaces the first occurrence of the search text old with new. This addition is also the default setting.

Example

DATA: myText type string.

myText = 'abcabcabcabcabc'.

REPLACE FIRST OCCURRENCE OF 'abc' IN myText WITH 'XYZ'.

returns: myText = 'XYZabcabcabcabc', sy-subrc = 0

Addition 2

... ALL OCCURRENCES OF

Effect

In the string text, replaces all patterns found that do not overlap. Bear in mind that the system searches the entire string and then replaces old with new.

Example 1

DATA: c4(4) TYPE C.

c4 = 'abab'.

REPLACE ALL OCCURRENCES OF 'ab' IN c4 WITH 'CCC'.

returns: c4 = 'CCCC', sy-subrc = 2

not c4 = 'CCCa', sy-subrc = 2. (as it would, if the system replaced each search string successively).

Example 2

DATA: myText type string.

myText = 'abcabcabcabcabc'.

REPLACE ALL OCCURRENCES OF 'abc' IN myText WITH 'XYZ'.

returns: myText = 'XYZXYZXYZXYZXYZ', sy-subrc = 0

Regards,

Swapna

Re: replace

Former Member — Mon, 30 Jun 2008 10:34:56 GMT

You can write:


data:
  zlv_char type char40.

translate zlv_char using ' _'.

Sorry, I see that Eric already gave the correct answer.

Regards,

John.

Edited by: John Heutmekers on Jun 30, 2008 12:35 PM

Re: replace

Former Member — Mon, 30 Jun 2008 10:35:37 GMT

Hi,

Try using translate

TRANSLATE <variablename> USING ' _' .

Regards,

Sai

Re: replace

sachin_mathapati — Mon, 30 Jun 2008 10:36:24 GMT

hi Imran,

Try translate Instead of Replace.

Regards,

Sachin M M

Re: replace

Former Member — Mon, 30 Jun 2008 10:38:21 GMT

Hi,

use this.. REPLACE ALL OCCURRENCES OF ' ' IN wa_final-last_name WITH '_'.

Re: replace

former_member188827 — Mon, 30 Jun 2008 10:44:22 GMT

try:

data str(50) VALUE 'abc def ghi'.

data: in type i, ind TYPE i.

in = STRLEN( str ).

WHILE ind lt in.

if str+ind(1) = ''.

move '_' to str+ind(1).

endif.

ind = ind + 1.

ENDWHILE.

WRITE / str.

plz reward points if dis helps

Re: replace

Former Member — Mon, 30 Jun 2008 10:52:38 GMT

This message was moderated.

Re: replace

Former Member — Mon, 30 Jun 2008 11:00:23 GMT

Hi imran ,

Try this once,

data:

w_char1(40) type c,

w_c type c value space,

w_char(40) type c ,

w_c1 type c value '_',

w_new type c.

w_char = ' hello hai how r u'.

condense w_char.

while w_char ne ' '.

w_new = w_char(1).

shift w_char left.

if w_new eq space.

replace w_new in w_char with w_c1.

endif.

concatenate w_char1 w_new into w_char1.

endwhile.

write w_char1.

Regards,

Rajitha.