topic error when trying to split in Application Development and Automation Discussions

error when trying to split

Former Member — Tue, 22 Apr 2008 14:01:22 GMT

Hi,

DATA: lv_zbnkl(8) TYPE c.

Data: l_chr(15) type c. ß-- NUMBER is SAME AS zbnkl LENGTH

Write i_reguh.-zbnkl to l_chr

IF L_CHR CA '-'.

SPLIT L_CHR AT '-' INTO lv_zbnkl.---->error

endif.

I am using above code but it is throwing an eror saying that unable to interpret lv_zbankl.

Former Member — Tue, 22 Apr 2008 14:04:30 GMT

U need to have atleast 2 variables .. when U split ..

write as ...

SPLIT L_CHR AT '-' INTO lv_zbnkl lv_zbnkl1.

Former Member — Tue, 22 Apr 2008 14:06:35 GMT

hi prince you r splitting a value into two ...but you specified the variables only one..al the end of the statement

SPLIT L_CHR AT '-' INTO lv_zbnkl and some field is required here..

regards,

venkat.

Former Member — Tue, 22 Apr 2008 14:07:51 GMT

hi,

do this way...


data : lv_other(10).

IF L_CHR CA '-'.
SPLIT L_CHR AT '-' INTO lv_zbnkl lv_other.
endif.

write : lv_zbnkl, lv_other.

Former Member — Tue, 22 Apr 2008 14:11:17 GMT

Hi,

Correct your code which is highted.

DATA: lv_zbnkl(8) TYPE c.

*DATA: lv_zbnkl_extra(7).*

Data: l_chr(15) type c. ß-- NUMBER is SAME AS zbnkl LENGTH

Write i_reguh.-zbnkl to l_chr

IF L_CHR CA '-'.

SPLIT L_CHR AT '-' INTO lv_zbnkl lv_zbnkl_extra.---->error

endif.