topic Re: Why not working this code? in Application Development and Automation Discussions

Why not working this code?

Former Member — Tue, 25 Mar 2008 12:34:45 GMT

Hi,

I want to use following part of code to exit the program whenever he wants. He should not have to enter a value into a required text area.

But not working?

What may be the problem?

PROCESS AFTER INPUT.

MODULE exit AT EXIT-COMMAND.

And the code is as follows:

MODULE EXIT INPUT.

LEAVE PROGRAM.

ENDMODULE. " EXIT INPUT

Re: Why not working this code?

dhruv_shah3 — Tue, 25 Mar 2008 12:38:53 GMT

YOu can use it like this...



MODULE USER_COMMAND_0100 INPUT.
CASE OK_CODE.
  WHEN 'EXIT'.
    LEAVE PROGRAM.
  WHEN 'ICON'.
    MESSAGE 'THIS IS INFORMATION' TYPE 'I'.
  WHEN 'BACK'.
    LEAVE TO SCREEN 0.
  WHEN 'CANCEL'.
    CLEAR OK_CODE.
  ENDCASE.

ENDMODULE.                 " USER_COMMAND_0100  INPUT

HTH

Regards,

Dhruv Shah

Re: Why not working this code?

rahulkavuri — Tue, 25 Mar 2008 12:38:53 GMT

First check whether it comes till LEAVE PROGRAM by setting a break-point..

If it is, then make a call as follows to leave the transaction

CALL TRANSACTION SESSION_MANAGER

This is generally the case when the user navigates to a second screen and makes a call to LEAVE PROGRAM...

Re: Why not working this code?

former_member480923 — Tue, 25 Mar 2008 12:40:44 GMT

Give the Function type for the button as E - Exit Command

Hope That Helps

Anirban M.

Re: Why not working this code?

Former Member — Tue, 25 Mar 2008 12:41:53 GMT

Hi,

If the text area is mandatory field, then it is not possible to go back without entering the some values into that.

Thanks,

Sriram Ponna.

Re: Why not working this code?

Former Member — Tue, 25 Mar 2008 12:42:37 GMT

hi,

make sure that u have given Function Type E ( Exit Command) to that button in GUI Status...